Answer:
y=5 and x=4
Step-by-step explanation:
So,the diagonals of a parallelogram bisect each other..
therefore,we have our two eqn
4x-2=3y-1------------(i)
3y-3=3x
or,y-1=x----------(ii)
Now,simply substitute value of x in eqn (i)
4(y-1)-2=3y-1
or,4y-4-2=3y-1
or,y=5
Again,substitute y=5 in eqn (ii)
5-1=x
therefore,
x=5
Hope it helps you!!!
10^2 since 10(10) = 100 and 10 is multiplied by itself twice.
2x^2+9x-6 i found this by subtracting 3x^2+7x from the other equation
Just make a triangle and an X and Y axis and reflect it over the Y axis. It's that simple. Then tell how you did it. Obviously it will be a reflection. Name the points (before and after) and you are done.
-Twix
Answer:
32
Step-by-step explanation:
Step 1: Define
f(x) = 3x² - 5x - 4
g(x) = -4x - 12
Step 2: Find f(g(x))
f(g(x)) = 3(-4x - 12)² - 5(-4x - 12) - 4
f(g(x)) = 3(16x² + 96x + 144) + 20x + 60 + 4
f(g(x)) = 48x² + 288x + 432 + 20x + 64
f(g(x)) = 48x² + 308x + 496
Step 3: Find f(g(-4))
f(g(-4)) = 48(-4)² + 308(-4) + 496
f(g(-4)) = 48(16) - 1232 + 496
f(g(-4)) = 768 - 736
f(g(-4)) = 32
