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Pani-rosa [81]
3 years ago
13

List the normal sequence of steps in the breakdown of hemoglobin.

Advanced Placement (AP)
2 answers:
spayn [35]3 years ago
8 0

Explanation:

The sequence of steps in the breakdown of hemoglobin arae:

1. The heme of hemoglobin releases the iron.

2. The heme then converted into biliverdin.

3. The biliverdin which is converted into bilirubin.

5. Bilirubin is broken down to Hemoglobin.

5. Hemoglobin is broken down by macrophages into heme and globin chains

igor_vitrenko [27]3 years ago
5 0
1. The heme of hemoglobin releases the iron. The heme then converted into biliverdin, which is converted into bilirubin.

2. Conjugated bilirubin is excreted as is then part of the bile into the small intestine. Bacteria of the intestine break down the bilirubin.

3. Some bilirubin derivatives converted into which is contribute to the color of feces.

4. Other biliurbin derivatives are reabsorbed from the intestine into the blood. These derivatives are excreted from the kidneys and contribute to the color of urine.

5. The globin chains of hemoglobin are broken down to individual amino acids and are metabolized or used to build new proteins.

6. Blood transports free bilirubin to the liver.

7. Blood transports iron in combination with transferrin to various tissues for storage or to the red bone marrow where it is used in the production of new hemoglobin.

8. Hemoglobin is broken down by macrophages into heme and globin chains.
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Explain in detail, how you solved the following problem: The first two terms of a sequence are 10 and 20. If each term after the
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Answer:

T_{2020} = 15

Explanation:

Given

T_1 = 10

T_2 = 20

Each term after the second term is the average of all of the preceding terms

Required:

Explain how to solve the 2020th term

Solve the 2020th term

Solving the 2020th term of a sequence using conventional method may be a little bit difficult but in questions like this, it's not.

The very first thing to do is to solve for the third term;

The value of the third term is the value of every other term after the second term of the sequence; So, what I'll do is that I'll assign the value of the third term to the 2020th term

<em>This is proved as follows;</em>

From the question, we have that "..... each term after the second term is the average of all of the preceding terms", in other words the MEAN

T_{n} = \frac{\sum T{k}}{n-1} ; where: k = 1 .... n -1

<em>Assume n = 3</em>

T_{3} = \frac{T_1 + T_2}{2}

<em>Multiply both sides by 2</em>

2 * T_{3} = \frac{T_1 + T_2}{2} * 2

2T_{3} = T_1 + T_2

<em>Assume n = 4</em>

T_{4} = \frac{T_1 + T_2 + T_3}{3}

T_{4} = \frac{(T_1 + T_2) + T_3}{3}

Substitute 2T_{3} = T_1 + T_2

T_{4} = \frac{2T_3 + T_3}{3}

T_{4} = \frac{3T_3}{3}

T_{4} = T_3

Assume n = 5

T_{5} = \frac{T_1 + T_2 + T_3 +T_4}{4}

T_{5} = \frac{(T_1 + T_2) + T_3 +(T_4)}{4}

Substitute 2T_{3} = T_1 + T_2 and T_{4} = T_3

T_{5} = \frac{2T_3 + T_3 +T_3}{4}

T_{5} = \frac{4T_3}{4}

T_{5} = \frac{(5-1)T_3}{5-1}

<em>Replace 5 with n</em>

T_{n} = \frac{(n-1)T_3}{n-1}

<em>(n-1) will definitely cancel out (n-1); So, we're left with</em>

T_{n} = T_3

Hence,

T_{2020} = T_3

Calculating T_3

T_{3} = \frac{10 + 20}{2}

T_{3} = \frac{30}{2}

T_{3} = 15

Recall that T_{2020} = T_3

T_{2020} = 15

3 0
4 years ago
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