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3 years ago

What is the answer to this problem ?

Mathematics

1 answer:

zlopas [31]3 years ago

8 0

Volume of cylinder = pi * r^3 * h

radius = diameter/2 = 6 in/2 = 3 in

volume = pi * (3 in)^2 * 18 in

volume = 508.9375... in^3

volume = 508.9 in^3

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Find the interest earned and the balance of the account: P=$650 R=4% T=2 Years

Dmitry_Shevchenko [17]

I have no idea.... Try to ask your teacher or your parents

8 0

3 years ago

Can you help me with the bottom three please?

nika2105 [10]

Answer:

6= 66.67%

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6 0

3 years ago

The pitchers for the home team had 12 strikeouts for 32 batters, while the pitchers for the visiting team had 15 strikeouts for

dimulka [17.4K]

Answer:

I disagree with the other answer.

Step-by-step explanation:

The reason for this is because if you have 12/32 for team 1, and 15/35 on team 2, then you do cross products(a type of shortcut).

12/32 15/35

1) Multiply 12 and 35= 420

2) Multiply 15 and 32= 480

3) Which number is greater?

Answer

TEAM 2..(or the visiting team)

5 0

2 years ago

PLEASE HELP.

krek1111 [17]

Answer:

Part a) The radii are segments AC and AD and the tangents are the segments CE and DE

Part b) $DE=4\sqrt{10}\ cm$

Step-by-step explanation:

Part a)

we know that

A radius is a line from any point on the circumference to the center of the circle

A tangent to a circle is a straight line which touches the circle at only one point. The tangent to a circle is perpendicular to the radius at the point of tangency.

In this problem

The radii are the segments AC and AD

The tangents are the segments CE and DE

Part b)

we know that

radius AC is perpendicular to the tangent CE

radius AD is perpendicular to the tangent DE

CE=DE

Triangle ACE is congruent with triangle ADE

Applying the Pythagoras Theorem

$AE^{2}=AC^{2}+CE^{2}$

substitute the values and solve for CE

$14^{2}=6^{2}+CE^{2}$

$CE^{2}=14^{2}-6^{2}$

$CE^{2}=160$

$CE=\sqrt{160}\ cm$

$CE=4\sqrt{10}\ cm$

remember that

CE=DE

$DE=4\sqrt{10}\ cm$

7 0

3 years ago

Math... find angle x...

choli [55]

Value of x is 76°

Step-by-step explanation:

Given :- ∠JIH = 107°

and, JDI = 31°

To find :- value of x

solution:- ∠JIH + ∠JID =180° (the sum of angles on a line are supplementary)

∠JID = 180° - 107°

∠JID = 73°

Now in ΔJID

∠JID = 73° and ∠JDI = 31°

by angle some property of Δ

so, ∠JDI + ∠JID + ∠DJI = 180°

= 31° + 73° + ∠DJI = 180°

= 104° + ∠DJI = 180°

∠DJI = 180° - 104°

∠DJI = 76°

now, ∠DJI = ∠AJF = ∠X

so, x = 76°

hence value of x is 76°

8 0

3 years ago