Question

Just help me please don’t ignore me

Answer 1

Answer:

• See brainly.com/question/23882263 for A and B parts of the first question

d)

• $HF = \sqrt{EH^2+EF^2} = \sqrt{2^2+3^2} = \sqrt{13}$

#2

• $d = \sqrt{2^2+5^2} = \sqrt{4+25} = \sqrt{29}$

#3

Diagonals are perpendicular. Side length of the rhombus:

• $a = \sqrt{(8/2)^2+(6/2)^2} = \sqrt{4^2+3^2} = \sqrt{25} = 5$

Perimeter:

• P = 4a = 4(5) = 20