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otez555 [7]
3 years ago
12

Just help me please don’t ignore me

Mathematics
1 answer:
aleksley [76]3 years ago
4 0

Answer:

  • <em>See brainly.com/question/23882263 for A and B parts of the first question</em>

d)

  • HF = \sqrt{EH^2+EF^2} = \sqrt{2^2+3^2} = \sqrt{13}

#2

  • d = \sqrt{2^2+5^2} = \sqrt{4+25}  = \sqrt{29}

#3

<u>Diagonals are perpendicular. Side length of the rhombus:</u>

  • a = \sqrt{(8/2)^2+(6/2)^2} = \sqrt{4^2+3^2} = \sqrt{25} = 5

<u>Perimeter:</u>

  • P = 4a = 4(5) = 20
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Ksivusya [100]
<h2>Answer:</h2>

The ratio of the area of region R to the area of region S is:

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<h2>Step-by-step explanation:</h2>

The sides of R are in the ratio : 2:3

Let the length of R be: 2x

and the width of R be: 3x

i.e. The perimeter of R is given by:

Perimeter\ of\ R=2(2x+3x)

( Since, the perimeter of a rectangle with length L and breadth or width B is given by:

Perimeter=2(L+B) )

Hence, we get:

Perimeter\ of\ R=2(5x)

i.e.

Perimeter\ of\ R=10x

Also, let " s " denote the side of the square region.

We know that the perimeter of a square with side " s " is given by:

\text{Perimeter\ of\ square}=4s

Now, it is given that:

The perimeters of square region S and rectangular region R are equal.

i.e.

4s=10x\\\\i.e.\\\\s=\dfrac{10x}{4}\\\\s=\dfrac{5x}{2}

Now, we know that the area of a square is given by:

\text{Area\ of\ square}=s^2

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\text{Area\ of\ Rectangle}=L\times B

Hence, we get:

\text{Area\ of\ square}=(\dfrac{5x}{2})^2=\dfrac{25x^2}{4}

and

\text{Area\ of\ Rectangle}=2x\times 3x

i.e.

\text{Area\ of\ Rectangle}=6x^2

Hence,

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=\dfrac{6x^2}{\dfrac{25x^2}{4}}\\\\=\dfrac{6x^2\times 4}{25x^2}\\\\=\dfrac{24}{25}

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