Answer:
A) T'(-3, 6) and V'(0, 3)
Step-by-step explanation:
In the picture attached, triangle TVW is shown.
Transforming points T and V according to the rule (x,y) -> (3/4x, 3/4y), we get:
T(-4, 8) -> (-4*3/4, 8*3/4) -> (-3, 6) which corresponds to T'
V(0, 4) -> (0*3/4, 4*3/4) -> (0, 3) which corresponds to V'
If "4/2/7" is all we have to work with, then PEMDAS rules will save the day. Do the division from left to right.
4/2 becomes 2. Then we have 2/7, a proper fraction. I don't see where an improper fraction would come from in this case.
7 because 7 x 7 is 49 but if you add 7 and 7 it gets to 14 7 is the answer
so if you do a different number you will be wrong
I don't see a drawing of the quadrilaterals, so I don't know what the perimeter of quadrilateral P is. But whatever the perimeter of P is, Q will be 1/3 of that. Perimeter is a length, so even though it may pertain to a 2-dimensional object, it is still a 1-dimensional, linear measure. When two objects are similar (same shape, but scaled up or down by a scale factor), all corresponding linear measures have the same scale factor.
If you were asked about area or volume, that would be a different matter. In the case of area, you would square the scale factor, and in the case of volume, you would cube the scale factor.
