The solution of 
are 1 + 2i and 1 – 2i
<u>Solution:</u>
Given, equation is
We have to find the roots of the given quadratic equation
Now, let us use the quadratic formula
--- (1)
<em><u>Let us determine the nature of roots:</u></em>
Here in a = 1 ; b = -2 ; c = 5
Since 
, the roots obtained will be complex conjugates.
Now plug in values in eqn 1, we get,
On solving we get,
we know that square root of -1 is "i" which is a complex number
Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i
Answer:
write 4/27 as the product of a prime raised to a power
Answer:
<h2>5, 7, 11</h2>
Step-by-step explanation:
A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers.
A prime number has only two divisors: 1 and itself.
Therefore, the prime numbers are:
5, 7 and 11.
12 is not a prime because 12 = 2 × 6 = 3 × 4.
12 has six divisors: 1, 2, 3, 4, 6 and 12.
Answer: -1.6 is not a possible r-value.
Step-by-step explanation:
R-values range from -1 to +1. Out of all these numbers, -1.6 does not belong. Hence, -1.6 is not a r-value.
Answer:
n - 1
Step-by-step explanation:
(n-1)(n-5) / 2(n+3) ×2(n+3) / (n-5)
Kindly check attached picture for simplification
