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Tema [17]
3 years ago
5

15. Which function contains the point (6,2)?”

Mathematics
1 answer:
Nataly_w [17]3 years ago
4 0

Answer:

Were is the other numbers i need to graph the others numbers i can not just graph (6,2)

Step-by-step explanation:

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Need Help ASAP due by end of class on these math problem
Y_Kistochka [10]
It’s 3y not just 3. You need to add the exponent as well
3 0
3 years ago
Which figure contains an angle bisector?
Anastaziya [24]

Answer: Figure 2.

Step-by-step explanation:

Suppose that we have an angle with measure ∠M, a bisector would be a line that divides this angle in two equal parts, such that each new angle has measures (∠M)/2

Then the correct option will be the one that has two equal angles.

In figure 2, we can see that RP divides the angle SRQ in two angles 52°, then RP is the bisector of the angle.

Then the correct option is figure 2.

6 0
2 years ago
The circle described by the equation <img src="https://tex.z-dn.net/?f=%28x-3%29%5E%7B2%7D%20%2B%28y%2B4%29%5E%7B2%7D%3D9" id="T
ElenaW [278]

Answer:

The point at which center of the image circle located is (-2, -3) so second option is correct.

Step-by-step explanation:

Given equation of circle is:

(x-3)^{2} + (y+4)^{2} = 9 (i)

The general equation of circle is mentioned below,

(x-h)^{2} + (y-k)^{2} = r^{2} (ii)

Here 'r' represents the radius of the circle and (h,k) shown the center of the circle.

By comparing equation (i) and equation (ii), we get

r^2 = 9

r = 3

(x-3)^{2} = (x-h)^{2}

(x-3) = (x-h)

h = 3

(y+4)^{2} = (y-k)^{2}

(y+4) = (y-k)

k = -4

So the center of given circle is (h,k) = (3,-4)

Also, the circle is translated 5 units left, that is towards the -x-axis. Therefore h = 3 - 5 = -2

Also, the circle is translated 1 unit up, that is towards the +y-axis. Therefore k = -4 + 1 = -3

Hence, the point at which center of the image circle located is (-2, -3) so second option is correct.

6 0
3 years ago
Read 2 more answers
Suppose the base and height of a triangle sum to 18 cm, and the area of the triangle is 36 square cm. if the base is larger than
pentagon [3]
<span>15-h)*h=40
15h-h^2=40
h^2-15h+40=0
solve for h by quadratic formula:

a=1, b=-15, c=20
ans:
h=3.47 or 11.53 cm (height)
b=15-h=11.53 or 3.47 cm (base)</span>
7 0
3 years ago
Which expresses 216:270 in its simple form
Ivanshal [37]

Answer:

4/5

Step-by-step explanation:

Steps to simplifying fractions

Find the GCD (or HCF) of numerator and denominator

GCD of 216 and 270 is 54

Divide both the numerator and denominator by the GCD

216 ÷ 54

270 ÷ 54

Reduced fraction:  

4

5

5 0
3 years ago
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