First we calculate the mass of carbon,
hydrogen and oxygen.
Mass of Carbon;<span>
Molar mass of CO</span>₂ is 44.009g/mol and molar mass of C = 12.011 g/mol
<span>Mass of Carbon in 14.08g CO2</span>₂ = 12.011/44.009 x 14.08 = 3.84
<span>
Mass Hydrogen;
Molar mass H</span>₂O is 18.0015g/mol and molar mass of H is 1.008and H₂ = 2.016
<span>Mass Hydrogen in 4.32g of H</span>₂O = 2.016/18.0015 x 4.32 = 0.48
<span>
<span>Mass of Oxygen
= total mas of tartaric acid – (mass of carbon + mass of hydrogen) = 12.01 -
(3.84+0.48) = 7.69</span>
Now divide carbon, hydrogen and oxygen through
their respective atomic masses: </span>
<span>C = 3.84/12.011 = 0.32
<span>H = 0.48/1.008 = 0.48
<span>O = 7.69/15.999 = 0.48
Now divide by smallest: </span>
C = 0.32/0.32 = 1 </span>
H = 0.48/0.32 = 1.5
O = 0.48/0.32 = 1.5
multiply by 2 to get whole integers: </span>
C = 1 x 2 = 2
H= 1.5 x 2 = 3
<span>O= 1.5 x 2 = 3
<span>Thus, the Empirical formula of tartaric acid =
C</span></span>₂H₃O₃
Answer:
Scientific modeling, Is the generation of a physical, conceptual, or mathematical representation of a real phenomenon that is difficult to observe directly. Scientific models are used to explain and predict the behavior of real objects or systems and are used in a variety of scientific disciplines, ranging from physics and chemistry to ecology and the Earth sciences. Although modeling is a central component of modern science, scientific models at best are approximations of the objects and systems that they represent—they are not exact replicas. Thus, scientists constantly are working to improve and refine models.
Drawings help people visualize as well as see the concepts that are trying to be seen.
I don't know how to figure out the other things.
Explanation:
Draw CO2, C in the middle and O on each side. O has 6 e- and C has 4, so 6+6+4= 14 e-.
Answer : Option C) Non metal.
Explanation : A non metal is the one which does has poor thermal conductivity, poor electrical conductivity, are usually brittle solids which are not malleable or ductile, they have little or no metallic luster at all, and they gain electrons easily.
These are the properties which are seen in a non metal.
