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Schach [20]
3 years ago
11

This is a group 2 element that is called the alkaline earth metals. It burns with a very bright light

Chemistry
1 answer:
erica [24]3 years ago
7 0

the alkaline eart metal s are

Beryllium

Magnesium

calcium

Strontium

barium


out of these Magnesium reacts with oxygen and produces bright light due to formation of MgO

all other metals also form oxides but the oxide of Mg is brightest

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What is the percent composition of chlorine in the compound Ba(ClO3)2?
tia_tia [17]

You're going to divide the mass of chlorine within the compound by the mass of the compound, and then multiply the result by 100 to get the answer

6 0
2 years ago
what is a photoelectric?explain the terms ground state and excited state with the help of labelled diagram
brilliants [131]

Answer: Photoelectric is characterized by or involving the emission of electrons from a surface by the action of light.

Photoelectric effect is the emission of electrons when a radiation of frequency higher than the threshold frequency falls on the surface of an element. The substance which undergoes photoelectric effect is called as photoelectric.

Ground state is the state representing the lowest energy  state.

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5 0
3 years ago
Does pressure decrease when a gas is removed
vovangra [49]

yes

Explanation:

the volume also decrease. as particles are removed from the space the gas is in, there is a decrease in the number of collisions.

4 0
3 years ago
How many moles of carbon are in 3.5 L?
SashulF [63]

Answer:

0.16mole

Explanation:

To solve this problem, we are going to assume that the number of moles of carbon to be determined is that at STP, standard temperature and pressure.

The number of moles of a substance at STP is given as;

 Number of moles  = \frac{volume}{22.4}  

Given volume  = 3.5L

Now, insert the parameters;

     Number of moles  = \frac{3.5}{22.4}   = 0.16mole

8 0
3 years ago
Us<br> What is the percent of O in<br> Cr2O3?<br> (Cr = 52.00 amu, O = 16.00 amu)<br> [? ]%
Gekata [30.6K]

The percent of O in  Cr₂O₃ : 31.58%

<h3>Further explanation</h3>

Given

Cr = 52.00 amu, O = 16.00 amu

Required

The percent of O

Solution

MW Cr₂O₃ = 2 x Ar Cr + 3 x Ar O

MW Cr₂O₃ = 2.52+3.16

MW Cr₂O₃ =152 amu

\tt \%O=\dfrac{3.Ar~O}{MW~Cr_2O_3}\times 100\%\\\\\%O=\dfrac{3.16}{152}\times 100\%\\\\\%O=31.58\%

8 0
2 years ago
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