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3 years ago

What will for if sodium give away one electron ?

Chemistry

1 answer:

Alja [10]3 years ago

8 0

Answer:

A sodium atom has one electron in the outer shell. A chlorine atom seven electrons in the outer shell. A sodium atom loses an electron to a chlorine atom. The sodium atom becomes a positive sodium ion.

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In the following reaction, how many grams of oxygen will react with 10.47 grams of benzene (C6H6)? 2C6H6 + 15O2 12CO2 + 6H2O The

Virty [35]

The balanced chemical reaction will be:

2C6H6 + 15O2 = 12CO2 + 6H2O

We are given the amount of benzene to react with oxygen gas. This will be our starting point.

10.47 g C6H6 ( 1 mol C6H6 / 78.1074 grams C6H6) (15 mol O2/2 mol C6H6 ) ( 32 g O2 / 1 mol O2) = 32.1711g O2

6 0

3 years ago

Read 2 more answers

A protein has an isoelectric point (pI) of 9. Which of the following statements best describes the state of this protein in aque

Brums [2.3K]

Answer:

The correct option is D

Explanation:

From the question we are told that

The pH of the aqueous solution is $pH = 7$

The isoelectric point is $pl = 9$

From the data given we see that the

$pH$ is below $pl$

So the protein will have a net positive charge

4 0

4 years ago

The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In t

Digiron [165]

Answer:

35.3124 g is the maximum mass of $H_2O$ that can be produced.

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

For $NH_3$ :-

Mass of $NH_3$ = 52.3 g

Molar mass of $NH_3$ = 17.031 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{52.3\ g}{17.031\ g/mol}$

$Moles\ of\ NH_3= 3.0709\ mol$

For $O_2$ :-

Given mass of $O_2$ = 52.3 g

Molar mass of $O_2$ = 31.9898 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{52.3\ g}{31.9898\ g/mol}$

$Moles\ of\ O_2=1.6349\ mol$

According to the given reaction:

$4NH_3+5O_2\rightarrow 4NO_4+6H_2O$

4 moles of $NH_3$ reacts with 5 moles of $O_2$

1 mole of $NH_3$ reacts with 5/4 moles of $O_2$

Also,

3.0709 moles of $NH_3$ reacts with $\frac{5}{4}\times 3.0709$ moles of $O_2$

Moles of $O_2$ = 3.8386 moles

Available moles of $O_2$ = 1.6349 moles

Limiting reagent is the one which is present in small amount. Thus, $O_2$ is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

5 moles of $O_2$ on reaction forms 6 moles of $H_2O$

1 mole of $O_2$ on reaction forms 6/5 moles of $H_2O$

Thus,

1.6349 mole of $O_2$ on reaction forms $\frac{6}{5}\times 1.6349$ moles of $H_2O$

Moles of $H_2O$ = 1.9618 moles

Molar mass of $H_2O$ = 18 g/mol

Mass of sodium sulfate = Moles × Molar mass = 1.9618 × 18 g = 35.3124 g

35.3124 g is the maximum mass of $H_2O$ that can be produced.

3 0

3 years ago

Read 2 more answers

6 of 16

Arte-miy333 [17]

Answer: D. Physical change

Explanation:

Phase changes are physical changes.

3 0

3 years ago

What would the products of a double-replacement reaction between ca3n2 and al2o3 be?

djyliett [7]

The equation for the reaction between Ca3N2 and Al2O3 wiil be;
Al2O3 + Ca3N2 = 2AIN +3CaO
Thus, the products of the reaction will be Aluminium Nitride and Burnt lime(Calcium oxide). A double displacement reaction, also known as a double replacement reaction or metathesis, is a reaction where two compounds react, and the positive ions and the anions switch places, forming two new compounds or products.

7 0

3 years ago