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LenaWriter [7]
3 years ago
11

In how many ways can a committee of 5 people be chosen from a total of 30 possible people?

Mathematics
1 answer:
Stolb23 [73]3 years ago
3 0

Answer:  142506

Step-by-step explanation:

Given : The total number of choices for people in committee = 30

The number of people need to be chosen =5

Since , here order doesn't matter, so we use combination.

The combination of r things taking from n at a time is given by :-

C(n,r)=\dfrac{n!}{(n-r)!r!}

Now, the number of possible combinations of 5 people be chosen from a total of 30 possible people :-

C(30,5)=\dfrac{30!}{(30-5)!5!}\\\\=\dfrac{30\times29\times28\times27\times26}{120}\\\\=142506

Hence, the committee can be made in 142506 ways.

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From the stemplot, it can be taken that:

Both were very consistent home run hitters, due to the great amount of seasons with at least 20 home runs. Bonds had the biggest outlier, with a season of 73 home runs, while Aaron distribution was less spread.

-------------------------------

  • From the stemplot, it can be taken that Bonds had the biggest outlier, which was the season with 73 home runs.
  • His season with the lowest amount of home runs was also less than Aaron, as he had a 5 home run season while Aaron lowest amount was 10.
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Thus, we can take that:

Both were very consistent home run hitters, due to the great amount of seasons with at least 20 home runs. Bonds had the biggest outlier, with a season of 73 home runs, while Aaron distribution was less spread.

A similar problem is given at brainly.com/question/24341344

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