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Aleksandr-060686 [28]
3 years ago
10

I need help pleaseee

Mathematics
1 answer:
laiz [17]3 years ago
8 0
7 because 3 times 7 is equals 21
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One number is one-third a second number. if the sum of the numbers is 48, find the numbers.
Gnoma [55]

First number assume A

Second number assume B

A= 1/3B ==> B= 3A

A+B = 48 ==> A+ 3A= 48

4A= 48 ==> A= 12

B= 3A= 36

8 0
3 years ago
PLEASE HELP!!<br> Solve for x and y<br> 1/3x-2=1/3x+3
goldfiish [28.3K]

Answer:

no solution, 1/3x - 2 ≠ 1/3x + 3

where is the 'y'?

Step-by-step explanation:

3 0
2 years ago
476 Marks<br> boole<br> Calculate the area of this triangle.<br> 17 cm<br> 8 cm<br> 15 cm
Naddika [18.5K]

Answer:

Step-by-step explanation:

sides =8 cm, 17 cm and 15 cm

Area of triangle by Hero's Formula,

S=a+b+c/2

S=17+8+15/2

S=40/2

S=20

A=\sqrt{s(s-a)(s-b)(s-c)}

A=\sqrt{20(20-17)(20-8)(20-15)}

A=\sqrt{(20)(3)(12)(5)}

A=\sqrt{3600}

A=60 cm^{2}

4 0
3 years ago
George Martin loves The Beatles. Honestly, who doesn’t? On George’s favorite Spotify playlist, 40% of the songs are by The Beatl
makvit [3.9K]

Answer:

17.5%

Step-by-step explanation:

First of all, see this situation as a cumulative binomial distribution. You have isolated trials with a probability of success. This makes it binomial. The wording of the question "what is the probability of at least half..." makes this cumulative.

There are a few ways to calculate this, and I'm not quite sure which way you're familiar with. I'll show the cumbersome way and use wolfram to make the calculation.

First, I'll calculate the probability for 15 success, given 30 trials.

30c15*0.4^15*0.6^15

Since the question asks for the probability of at least 15 success, I'll have to make a calculation for the probability of 16 successes, then 17, and so on. Then I'll have to add all the probabilities together. So, I'll use wolfram for that (see attached)

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=5y%2B7%20%5Cleq%20-3%20or%203y%20-2%20%5Cgeq%2013" id="TexFormula1" title="5y+7 \leq -3 or 3y
liberstina [14]
5y + 7 < = -3
5y < = -3 - 7
5y < = -10
y < = -10/5
y < = -2

3y - 2 > = 13
3y > = 13 + 2
3y > = 15
y > = 15/3
y > = 5
7 0
3 years ago
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