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gizmo_the_mogwai [7]
3 years ago
9

Find the total cost for a $64 gift that has been marked up 30%. *

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
5 0
30% of $64 is 19.2
19.2+64 = 83.2
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5×100+9×1+41/100 as a decimal
liubo4ka [24]

Answer:

Step-by-step explanation:

<u>P</u>arentheses <u>E</u>xponents <u>M</u>ultiplication <u>D</u>ivision <u>A</u>ddition <u>S</u>ubtraction

5X100=500  and 9X1=9 and 41/100=0.41 Then put them back into the equation

5X100+9X1+41/100=

 500  +  9  +  0.41  =  Now add.  509.41

3 0
3 years ago
How many time does 2 go into 19
BigorU [14]
Hello There @Diamondinthesky123 (Cute Username)

When you state the question, "How many times does 2 go into 19", I assume your talking about Long Division. (Not so long in this case)

In this case, we would divide 19 by 2, resulting in 9 with a remainder of 1. 
Thats It! :)

I hope I helped, Have a great Day!

Thank you,
Darian D. 
4 0
3 years ago
8x²y³ (3 is negative exponent)<br><br> x = 4<br> y = 2
Dennis_Churaev [7]

Answer:

8 x 16 x 8

64 x 16

1024 is .....

8 0
2 years ago
Read 2 more answers
Find the 2nd Derivative:<br> f(x) = 3x⁴ + 2x² - 8x + 4
ad-work [718]

Answer:

f''(x)=36x^2+4

Step-by-step explanation:

Let's start by finding the first derivative of f(x)= 3x^4+2x^2-8x+4. We can do so by using the power rule for derivatives.

The power rule states that:

  • \frac{d}{dx} (x^n) = n \times x^n^-^1

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

Let's apply the power rule to the function f(x).

  • \frac{d}{dx} (3x^4+2x^2-8x+4)

Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

  • \frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)

Simplify the equation.

  • \frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)
  • \frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8(1)+0)
  • \frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8)
  • f'(x)=12x^3+4x-8

Now, this is only the first derivative of the function f(x). Let's find the second derivative by applying the power rule once again, but this time to the first derivative, f'(x).

  • \frac{d}{d} (f'x) = \frac{d}{dx} (12x^3+4x-8)
  • \frac{d}{dx} (12x^3+4x-8) = ((3)12x^3^-^1 + (1)4x^1^-^1 - (0)8)

Simplify the equation.

  • \frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4x^0 - 0)
  • \frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4(1) - 0)
  • \frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4 )

Therefore, this is the 2nd derivative of the function f(x).

We can say that: f''(x)=36x^2+4

6 0
2 years ago
Read 2 more answers
Will give brainliest
posledela

Answer:

I think its the lifo method im not sure but i had a question like this in class

5 0
2 years ago
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