Answer:
the ratio of the kinetic energy of an electron to that of a proton if their wavelengths are equal is 1835.16 .
Explanation:
We know, wavelength is expressed in terms of Kinetic Energy by :
Therefore , 
It is given that both electron and proton have same wavelength.
Therefore,
.... equation 1.
.... equation 2.
Now, dividing equation 1 by 2 .
We get ,
Putting value of mass of electron = 
and mass of proton = 
We get :
Hence , this is the required solution.
Look first for the relation between deBroglie wavelength (λ) and kinetic energy (K):
K = ½mv²
v = √(2K/m)
λ = h/(mv)
= h/(m√(2K/m))
= h/√(2Km)
So λ is proportional to 1/√K.
in the potential well the potential energy is zero, so completely the electron's energy is in the shape of kinetic energy:
K = 6U₀
Outer the potential well the potential energy is U₀, so
K = 5U₀
(because kinetic and potential energies add up to 6U₀)
Therefore, the ratio of the de Broglie wavelength of the electron in the region x>L (outside the well) to the wavelength for 0<x<L (inside the well) is:
1/√(5U₀) : 1/√(6U₀)
= √6 : √5
Well you could see it's physical properties have the same descriptions corresponding to a liquid. (Sorry if this doesn't help you..)
Which is a substance that takes the shape and volume of its container?
liquid
Fnet =ma
1560)(1.3102)
the answer is b
