First there are many ways to approach this problem. The simplest and most direct in my opinion is this approach:
vf^2=v1^2+2ad
so when the height reaches a maximum of 35m the velocity is zero for a split second before starting to fall. So we set vf=0 and solve for v1.
v1=sqrt(2gd)=sqrt(2*9.8*35)= 26.2m/s
for initial velocity needed to reach 35m height.
Any questions please ask!
To solve this problem we will make a graph that allows us to understand the components acting on the body. In this way we will have the centripetal Force and the Force by gravity generating a total component. If we take both forces and get the trigonometric ratio of the tangent we would have the angle is,
Dividing both.
Therefore the angle that should the curve be banked is 15.608°
Both matter and energy can eneter and exit an <span>Open System only. A.</span>
Answer:
V=22.4m/s;T=2.29s
Explanation:
We will use two formulas in order to solve this problem. To determine the velocity at the bottom we can use potential and kinetic energy to solve for the velocity and use the uniformly accelerated displacement formula:
Solving for velocity using equation 1:
Solving for time in equation 2: