Answer: 
Step-by-step explanation:

a=2
b=-9
c=5





The third one 02 2/5 is the answer
Hmmmmmm
Let me think for a second
Answer:
C.
and
Step-by-step explanation:
You have the quadratic function
to find the solutions for this equation we are going to use Bhaskara's Formula.
For the quadratic functions
with
the Bhaskara's Formula is:


It usually has two solutions.
Then we have
where a=2, b=-1 and c=1. Applying the formula:

Observation: 

And,

Then the correct answer is option C.
and