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makvit [3.9K]
4 years ago
5

The concentration of iodide ions in a solution made by mixing 0.193 m barium iodide and 0.250 m sodium iodide ________. 0.443 m

0.636 m 0.0643 m 0.579 m 0.193 m
Chemistry
1 answer:
Luden [163]4 years ago
4 0
The iodide  ion  concentration in the  mixture is=iodide concentration in dissociation  of  barium  iodide  plus  iodide concentration in  dissociation  of sodium iodide

The  ionic  equation  for  dissociation  of  barium  iodide  is
BaI2 ---> Ba2+   +  2 I-
Since  the  ratio  of  Bal2  to l- is 1:2  hence concentration  of iodide  ions  is  2  x0.193 =0.386M

the  ionic equation  for dissociation  of sodium  iodide  
Nal--->Na+  +  l-
since the ratio of  Nal  to  l-  is 1:1 the concentration  of iodide  ion  is o.250M

The  concentration of  iodide  in  the mixture  is  therefore  0.386M +0.250M=0.636M

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A balloon filled with 0.500 L of air at sea level is submerged in the water to a depth that produces a pressure of 3.25 atm. Wha
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If the hydroxide ion concentration of a solution is 3.26 x 10-6 M, is it an acidic or a basic solution?
sladkih [1.3K]

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We were given that hydroxide ion concentration [OH-] as 3.26 x 10-6 M

But We know thar

[OH-] [H+] = 1 × 10^-14

To get the Hydrogen ion [H+] concentration, we have that

[H+] = 1 × 10^-14 M/[OH-]

= 1 × 10^-14 M/3.26 x 10-6 M

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