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yuradex [85]
3 years ago
13

Combustion reactions are most conveniently studied _____. hints combustion reactions are most conveniently studied _____. there

is no way to study a combustion reaction conveniently using a beaker and a thermometer using constant-pressure calorimetry using constant-volume calorimetry
Chemistry
1 answer:
Luden [163]3 years ago
3 0
By using a constant-volume calorimetry or also called as bomb calorimeter the combustion are most conveniently. So base on your choices the answer is using a constant-volume calorimetry. A constant-volume calorimetry or known as bomb calorimeter is<span> used in measuring the heat of combustion of a particular reaction.</span>
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3.65 gram of hcl is dissolved in 180 gram of water. Find the total number of molecules of hydrogen​
Morgarella [4.7K]

Answer:

Molec_{\ H_{tot}}=1.206x10^{25}molec

Explanation:

Hello.

In this case, taking into account that HCl has one molecule of hydrogen per mole of compound which weights 36.45 g/mol, we compute the number of molecules of hydrogen in hydrochloric acid by considering the given mass and the Avogadro's number:

molec_{\ H}=3.65gHCl*\frac{1molHCl}{36.45gHCl} *\frac{1molH}{1molHCl}*\frac{6.022x10^{23}molec_\ H}{1molH}  =6.03x10^{22}molec

Now, from the 180 g of water, we see two hydrogen molecules per molecule of water, thus, by also using the Avogadro's number we compute the molecules of hydrogen in water:

molec_{\ H}=180gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O}*\frac{6.022x10^{23}molec_\ H}{1molH}  =1.20x10^{25}molec

Thus, the total number of molecules turns out:

Molec_{\ H_{tot}}=6.03x10^{22}+1.20x10^{25}\\\\Molec_{\ H_{tot}}=1.206x10^{25}molec

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