How did you get 0.36 from 7/20

What is 395.20 divided by 5 rounded

olchik [2.2K]

I think it is 395.20 / 5 = 79.04, rounded down to 79

3 0

2 years ago

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Find the value of x that will make A and B parallel

Snezhnost [94]

I think x=10
4x=3x+10
subtract 3x from both sides and you get x=10

4 0

3 years ago

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A student who is trying to write a paper for a course has a choice of two topics, A and B. If topic A is chosen, the student wil

algol13

Answer:

P(Topic A) = 0.91

P(Topic B) = 0.9163

The student should choose Topic B to maximize the probability of writing a good paper because P(Topic B)>P(Topic A).

Step-by-step explanation:

If Topic A is chosen, 2 books will be ordered (n=2)

If topic B is chosen, 4 books will be ordered (n=4)

Probability that a book arrives in time (p) = 0.7

Probability that a book does not arrive in time (q) = 1 - p = 1 - 0.7 = 0.3

We will use the binomial distribution to find out which topic should the student choose to maximize the probability of writing a good paper. The binomial distribution formula is:

P(X=x) = ⁿCˣ pˣ qⁿ⁻ˣ

where p = probability of success

q = probability of failure

n = total no. of trials

x = no. of successful trials

For Topic A, n = 2, p=0.7 and q=0.3. If topic A is chosen, the student will use at least half the books i.e. he will use either 1 or 2 books. So,

P(Topic A) = P(X=1) + P(X=2)

=²C₁ (0.7)¹(0.3)²⁻¹ + ²C₂ (0.7)²(0.3)²⁻²

= 0.42 + 0.49

P(Topic A) = 0.91

For topic B, n=4, p=0.7 and q=0.3. If topic B is chosen, the student will choose 2 or more books i.e. 2, 3 or 4 books.

P(Topic B) = P(X=2) + P(X=3) + P(X=4)

= ⁴C₂ (0.7)²(0.3)⁴⁻² + ⁴C₃ (0.7)³(0.3)⁴⁻³ + ⁴C₄ (0.7)⁴(0.3)⁴⁻⁴

= 0.2646 + 0.4116 + 0.2401

P(Topic B) = 0.9163

The student should choose Topic B to maximize the probability of writing a good paper because P(Topic B)>P(Topic A) as calculated above.

3 0

3 years ago

Which of these triangle pairs can be mapped to each other using a translation and a rotation about point A?

Vladimir79 [104]

Answer:

Figure A

Step-by-step explanation:

See the attached figure which represents the given options

We are to select the correct pair of triangles that can be mapped to each other using a translation and a rotation about point A.

As shown: point A will map to point L, point R will map to point P and point Q will map to point K.

we will check the options:

Figure A: the triangle ARQ and LPK can be mapped to each other using a translation and a rotation about point A.

Figure B: the triangle ARQ and LPK can be mapped to each other using a translation and a reflection about the line RA.

Figure C: the triangle ARQ and LPK can be mapped to each other using a translation and a reflection about the line QA.

Figure D: the triangle ARQ and LPK can be mapped to each other using a rotation about point A.

So, the answer is figure A

The triangle pairs of figure A can be mapped to each other using a translation and a rotation about point A.

3 0

3 years ago

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The first five terms of a pattern are shown.

Andrej [43]

Answer:

C

Step-by-step explanation:

There is a common ratio between consecutive term in the sequence, that is

$\frac{3}{10}$ ÷ $\frac{3}{100}$ = 3 ÷ $\frac{3}{10}$ = 30 ÷ 3 = 300 ÷ 30 = 10

This indicates the sequence is geometric with n th term

$a_{n}$ = a $(r)^{n-1}$

where a is the first term and r the common ratio

Here a = $\frac{3}{100}$ and r = 10 , thus

$a_{n}$ = $\frac{3}{100}$ $(10)^{n-1}$

= $\frac{3}{10^{2} }$ × $10^{n-1}$

= 3 × $10^{-2}$ × $10^{n-1}$

= 3 × $10^{n-3}$

Thus

$a_{n}$ = 3 $(10)^{n-3}$ → C

6 0

3 years ago