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bija089 [108]
3 years ago
9

How did you get 0.36 from 7/20

Mathematics
1 answer:
Tema [17]3 years ago
7 0
I'm confused when I did it I got .35 and you divide
hope it helped

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What is 395.20 divided by 5 rounded
olchik [2.2K]
I think it is 395.20 / 5 = 79.04, rounded down to 79
3 0
2 years ago
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Find the value of x that will make A and B parallel
Snezhnost [94]
I think x=10
4x=3x+10
subtract 3x from both sides and you get x=10
4 0
3 years ago
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A student who is trying to write a paper for a course has a choice of two topics, A and B. If topic A is chosen, the student wil
algol13

Answer:

P(Topic A) = 0.91

P(Topic B) = 0.9163

The student should choose Topic B to maximize the probability of writing a good paper because P(Topic B)>P(Topic A).

Step-by-step explanation:

If Topic A is chosen, 2 books will be ordered (n=2)

If topic B is chosen, 4 books will be ordered (n=4)

Probability that a book arrives in time (p) = 0.7

Probability that a book does not arrive in time (q) = 1 - p = 1 - 0.7 = 0.3

We will <u>use the binomial distribution</u> to find out which topic should the student choose to maximize the probability of writing a good paper. The binomial distribution formula is:

P(X=x) = ⁿCˣ pˣ qⁿ⁻ˣ

where p = probability of success

           q = probability of failure

           n = total no. of trials

           x = no. of successful trials

For Topic A, n = 2, p=0.7 and q=0.3. If topic A is chosen, the student will use at least half the books i.e. he will use either 1 or 2 books. So,

P(Topic A) = P(X=1) + P(X=2)

                 =²C₁ (0.7)¹(0.3)²⁻¹ + ²C₂ (0.7)²(0.3)²⁻²

                 = 0.42 + 0.49

P(Topic A) = 0.91

For topic B, n=4, p=0.7 and q=0.3. If topic B is chosen, the student will choose 2 or more books i.e. 2, 3 or 4 books.

P(Topic B) = P(X=2) + P(X=3) + P(X=4)

                  = ⁴C₂ (0.7)²(0.3)⁴⁻² + ⁴C₃ (0.7)³(0.3)⁴⁻³ + ⁴C₄ (0.7)⁴(0.3)⁴⁻⁴

                  = 0.2646 + 0.4116 + 0.2401

P(Topic B) = 0.9163

The student should choose Topic B to maximize the probability of writing a good paper because P(Topic B)>P(Topic A) as calculated above.

3 0
3 years ago
Which of these triangle pairs can be mapped to each other using a translation and a rotation about point A?
Vladimir79 [104]

Answer:

<u>Figure A</u>

Step-by-step explanation:

See the attached figure which represents the given options

We are to select the correct pair of triangles that can be mapped to each other using a translation and a rotation about point A.

As shown: point A will map to point L, point R will map to point P and point Q will map to point K.

we will check the options:

<u>Figure A</u>: the triangle ARQ and LPK can be mapped to each other using a translation and a rotation about point A.

<u>Figure B: </u> the triangle ARQ and LPK can be mapped to each other using a translation and a reflection about the line RA.

<u>Figure C:</u> the triangle ARQ and LPK can be mapped to each other using a translation and a reflection about the line QA.

<u>Figure D:</u> the triangle ARQ and LPK can be mapped to each other using a rotation about point A.

So, the answer is figure A

<u>The triangle pairs of figure A can be mapped to each other using a translation and a rotation about point A.</u>

3 0
3 years ago
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The first five terms of a pattern are shown.
Andrej [43]

Answer:

C

Step-by-step explanation:

There is a common ratio between consecutive term in the sequence, that is

\frac{3}{10} ÷ \frac{3}{100} = 3 ÷ \frac{3}{10} = 30 ÷ 3 = 300 ÷ 30 = 10

This indicates the sequence is geometric with n th term

a_{n} = a(r)^{n-1}

where a is the first term and r the common ratio

Here a = \frac{3}{100} and r = 10 , thus

a_{n} = \frac{3}{100} (10)^{n-1}

    = \frac{3}{10^{2} } × 10^{n-1}

    = 3 × 10^{-2} × 10^{n-1}

    = 3 × 10^{n-3}

Thus

a_{n} = 3(10)^{n-3} → C

6 0
3 years ago
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