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3 years ago

How can parallel lines be used to compare figures E and F? Explain your reasoning.

Mathematics

1 answer:

Aneli [31]3 years ago

3 0

Answer:

The similarities are

1) The length of E and F can be described by two parallel lines spaced 3 blocks apart where the parallel line on the left of both E and F is 2 blocks long, while the parallel line on the right is one block long

2) Both height of E and F can be described by two parallel lines spaced 2 blocks apart where the parallel line on the top of both E and F is 3 blocks long, while the parallel line at the bottom is one block long

3) The interior of E an F can be described by parallel lines 2 blocks long in the horizontal portion and one block long in the vertical portion

The differences are

1) The difference between E and F is that the parallel lines used for the construction of E are all one block higher than that of F

2) The other difference is that all the lines used for the construction of the figure E are 3 blocks to the left of those used for the construction of F

Figure F is essentially the translation of figure E three blocks to right and one block down

Step-by-step explanation:

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Determine the mean absolute deviation of the data.9, 7, 11, 10, 8

Darya [45]

Answer:

mean=average which means you add all of the numbers and divide by the number of numbers there are, which sounds pretty confusing, but i'll show you! 9+7+11+10+8=45, now you divide 45 by 5, which is how many numbers there are that we had to add. 45 divided by 5 is 9, which means the MEAN/average is 9!

Step-by-step explanation:

hope this helps!

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3 years ago

Find f(−2) given that f(x)=2x2−3x+7.

Sedaia [141]

Answer:

21.

Step-by-step explanation:

f(x) = 2x^2 - 3x + 7.

When x = -2,

f(-2) = 2(-2)^2 - 3(-2) + 7

= 2(4) - (-6) + 7

= 8 + 6 + 7

= 21.

3 0

3 years ago

Read 2 more answers

Which two properties of equality could Zoe use to finish solving for x

7nadin3 [17]

3x-4= - 10
add both side 4 so its a addition property
3x=- 6
now divide both side 3 so it is a <span>division property.
so x=-2</span>

4 0

3 years ago

What is the solution to the following system of equations? x+2y=2 x-2y=-2

Tcecarenko [31]

All in all you would get the answer x+y=1.

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3 years ago

We are conducting a hypothesis test to determine if fewer than 80% of ST 311 Hybrid students complete all modules before class.

Juli2301 [7.4K]

Answer:

$z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124$

Null hypothesis: $p\geq 0.8$

Alternative hypothesis: $p < 0.8$

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis: $p\leq 0.8$

Alternative hypothesis: $p > 0.8$

$p_v =P(Z>2.124)=0.013$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

n=110 represent the random sample taken

X=97 represent the students who completed the modules before class

$\hat p=\frac{97}{110}=0.882$ estimated proportion of students who completed the modules before class

$p_o=0.8$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v{/tex} represent the p value (variable of interest) 2) Concepts and formulas to use We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.8 or 80%: Null hypothesis:[tex]p\geq 0.8$

Alternative hypothesis: $p < 0.8$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis: $p\leq 0.8$

Alternative hypothesis: $p > 0.8$

$p_v =P(Z>2.124)=0.013$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

5 0

3 years ago