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3 years ago

How can parallel lines be used to compare figures E and F? Explain your reasoning.

Mathematics

1 answer:

Aneli [31]3 years ago

3 0

Answer:

The similarities are

1) The length of E and F can be described by two parallel lines spaced 3 blocks apart where the parallel line on the left of both E and F is 2 blocks long, while the parallel line on the right is one block long

2) Both height of E and F can be described by two parallel lines spaced 2 blocks apart where the parallel line on the top of both E and F is 3 blocks long, while the parallel line at the bottom is one block long

3) The interior of E an F can be described by parallel lines 2 blocks long in the horizontal portion and one block long in the vertical portion

The differences are

1) The difference between E and F is that the parallel lines used for the construction of E are all one block higher than that of F

2) The other difference is that all the lines used for the construction of the figure E are 3 blocks to the left of those used for the construction of F

Figure F is essentially the translation of figure E three blocks to right and one block down

Step-by-step explanation:

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Value of x after the statement "if P(x) then x 1" is executed where P(x): > 1

ziro4ka [17]

The values of x after the statement are:

b) If x=1, then the statement P(1)="1>1" is false, and thus the value of x is equal to 1 after the statement "P(x) then x := 1".
c) If x=2, then the statement P(2)="2>1" is true, and thus the value of x is equal to 1 after the statement "if P(x) then x := 1".

<h3>What is Discrete Mathematics?</h3>

This refers to the field of mathematics that studies mathematical structures and views them as discrete, rather than continuous and they include integers, statements, etc.

Therefore, if we consider the statement "if P(x) then x:=1" which is equivalent to "if x>1 then x:=1", then we can see that If x=1, then the statement P(1)="1>1" is false

Read more about discrete mathematics here:

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2 years ago

8. In an examination 40% of the students failed. The number of students that passed was 180. How many students failed?

EastWind [94]

Answer:

Neither. 72 students failed.

Step-by-step explanation:

40% of 180 is 72

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3 years ago

Read 2 more answers

What is the value of x in the equation

Nastasia [14]

Answer:

Step-by-step explanation:

$\frac{1}{3x} - \frac{1}{2} = 18 \frac{1}{2} \\ \\ \frac{1}{3x} - \frac{1}{2} = \frac{37}{2} \\ \\ \frac{1}{3x} = \frac{37}{2} - \frac{1}{2} \\ \\ \frac{1}{3x} = \frac{37 - 1}{2} \\ \\ \frac{1}{3x} = \frac{36}{2} \\ \\ \frac{1}{3x} = 18 \\ \\ 1 = 54x$

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2 years ago

Which of the following statements is logically equivalent to "If I study, then I get better grades"? If I do not study, then I d

saul85 [17]

It would go along with, "if I get better grades, then I study."

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3 years ago

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P(X< ) 1-P(X> ) A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball

Mashutka [201]

Answer:

19.49% probability that no more than 16 of them are strikes

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .