Answer:
Step-by-step explanation:
The tough part of this question is figuring out what to do with √(7^2). You could do it by expanding the square. √(7^2) = √49
Now what is the square root of 49? Is it not 7?
√49 = 7
7^6 * 7^1
7 ^(6 + 1)
7 ^ 7
Yes, you made an algebraic error. By multiplying 18 x 4, you messed up on order of operations.
(x+9)(x+2)*4
becomes:
(x^2+11x+18)*4
= 4x^2 + 44x + 72
anyway, this is how I would do this problem:
(x+9)(x+2)(4) = 912
(x+9)(x+2) = 228
x^2 + 11x + 18 = 228
x^2 + 11x - 220 = 0
(x+21)(x-10) = 0
x = -21 or 10
The dimensions can't be negative, so we only use x = 10
The dimensions are then 10+9, 10+2, 4
or 19, 12, 4
Answer:
the ratio is 9: 25
Step by step calculation:
![\sqrt[3]{125} = 5 \\ 5 {}^{2} = 25 \\ \sqrt[3]{27} = 3 \\ 3 {}^{2 } = 9 \\](https://tex.z-dn.net/?f=%20%20%5Csqrt%5B3%5D%7B125%7D%20%20%3D%205%20%5C%5C%205%20%7B%7D%5E%7B2%7D%20%20%3D%2025%20%5C%5C%20%20%5Csqrt%5B3%5D%7B27%7D%20%20%3D%203%20%5C%5C%203%20%7B%7D%5E%7B2%20%7D%20%20%3D%209%20%5C%5C%20)
Answer:
x=√
33
/3
,
−
√
33
/3
Step-by-step explanation:
