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Greeley [361]
3 years ago
6

Please simplify 7^6 √ 7^2

Mathematics
2 answers:
daser333 [38]3 years ago
6 0

Answer:

Step-by-step explanation:

The tough part of this question is figuring out what to do with √(7^2). You could do it by expanding the square. √(7^2) = √49

Now what is the square root of 49? Is it not 7?

√49 = 7

7^6 * 7^1

7 ^(6 + 1)

7 ^ 7

Reptile [31]3 years ago
4 0

Answer:

49

Step-by-step explanation:

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If a function is derivable at a point it is also continous at that point explain why?
Artyom0805 [142]
For a function to have a derivative in a point has to be continuous at the point, that is, it has to be defined at that point, other wise the derivative would be meaningless.
5 0
4 years ago
Eddie Foster packs and seals pens at rate of $0.235 per pack. At the end of his eight-hour
uysha [10]

Answer:

$112.80

Step-by-step explanation:

If he earns $0.235 per pack, and there are 480 packs, then our equation is:

0.235 x 480 = $112.80

5 0
3 years ago
Which equation does NOT represent a proportional relationship between two variables with the constant of proportinality of? 1/2
Dimas [21]

Answer:

(D) y=x+\frac{1}{2}

Step-by-step explanation:

Two variables x and y are proportionally related  if they can be written in the form y=kx, where k is the constant of proportionality.

From the given options, if k=\frac{1}{2}

(B)y=\frac{1}{2}x is of the form y=kx

(C)y=\frac{3}{6}x is of the form y=kx with k=\frac{1}{2} as \frac{3}{6}=\frac{1}{2} in its lowest form.

(C)y=0.5x is of the form y=kx with k=\frac{1}{2} as 0.5=\frac{1}{2} in fractional form.

On the Contrary,

In Option D, y=x+\frac{1}{2} does not represent a proportional relationship between x and y. The constant of proportion is supposed to be a product of x.

6 0
4 years ago
Which table does NOT show y as a function of x
Pavlova-9 [17]

Answer:

h

Step-by-step explanation:

x can not repeat itself

4 0
3 years ago
Use the Remainder Theorem to determine which of the roots are roots of F(x). Show your work.
Brums [2.3K]

Answer:    x1=1   x2=-2  and x3=2

Step-by-step explanation:

1st   x1=1 is 1 of the roots , so

F(1)=1-1-4+4=0 - true

So lets divide x^3-x^2-4x+4 by (x-x1), i.e  (x^3-x^2-4x+4) /(x-1)=(x^2-4)

x^2-4 can be factorized as (x-2)*(x+2)

So x^3-x^2-4x+4=(x-1)*(x^2-4)=(x-1)(x-2)*(x+2)

So there are 3 dofferent roots:

x1=1   x2=-2  and x3=2

3 0
3 years ago
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