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aksik [14]
3 years ago
13

Find two numbers that round to 35.4 when rounded to the nearest tenth.Write the numbers in the box.

Mathematics
2 answers:
hodyreva [135]3 years ago
4 0
35.39, 35.38, 35.37, 35.36 are some numbers that round to 35.4 when rounded to the nearest tenth
Marrrta [24]3 years ago
4 0

Answer:  The two numbers that round to 35.4 when rounded to the nearest tenth are 35.38 and 35.41.

Step-by-step explanation:  We are given to find two numbers that round to 35.4 when rounded to the nearest tenth.

We know that

the numbers that will round to 35.4 will lie from 35.35 to 35.44.

That is, the numbers are 35.35, 35.36, 35.37, 35.38, 35.39, 35.41, 35.42, 35.43 and 35.44.

Therefore, two of the numbers are 35.38 and 35.41.

Thus, the two numbers that round to 35.4 when rounded to the nearest tenth are 35.38 and 35.41.

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Given: sin(18m-12)=cos(7m+2), find the value of m.
V125BC [204]

Answer:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

Step-by-step explanation:

Solve for m:

-cos(7 m + 2) sin(12 - 18 m) = 0

Multiply both sides by -1:

cos(7 m + 2) sin(12 - 18 m) = 0

Split into two equations:

cos(7 m + 2) = 0 or sin(12 - 18 m) = 0

Take the inverse cosine of both sides:

7 m + 2 = π n_1 + π/2 for n_1 element Z

or sin(12 - 18 m) = 0

Subtract 2 from both sides:

7 m = -2 + π/2 + π n_1 for n_1 element Z

or sin(12 - 18 m) = 0

Divide both sides by 7:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or sin(12 - 18 m) = 0

Take the inverse sine of both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or 12 - 18 m = π n_2 for n_2 element Z

Subtract 12 from both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or -18 m = π n_2 - 12 for n_2 element Z

Divide both sides by -18:

Answer: m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

3 0
3 years ago
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2/5*3=2/5*3/1=6/5

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