Answer:
Volume = (24x⁵ + 78x⁴ - 147x³ - 624x² - 360x)
Step-by-step explanation:
Container given in the picture is in the shape of a cuboid.
And volume of a cuboid is measured by the expression,
Volume of a cuboid = Length × width × height
Now substitute the measure of the container's dimensions given in the picture
Volume = (4x² + 3x)(x²- 8)(6x + 15)
= [(4x² + 3x)(x²- 8)](6x + 15)
= [4x²(x² - 8) + 3x(x² - 8)](6x + 15)
= (4x⁴ - 32x² + 3x³ - 24x)(6x + 15)
= (4x⁴ + 3x³ - 32x² - 24x)(6x + 15)
= 6x(4x⁴ + 3x³ - 32x² - 24x) + 15(4x⁴ + 3x³ - 32x² - 24x)
= 24x⁵+ 18x⁴ - 192x³ - 144x² + 60x⁴ + 45x³ - 480x² - 360x
= 24x⁵ + 78x⁴ - 147x³ - 624x² - 360x
ans is b...multiply eqn 1 by -2 and eqn 2 by 3
=》 -6x + 10y = 4...eqn 3
=》 6x + 3y = 9...eqn 4
add eqn 3 and 4...
=》13y = 13
=》y =1 and x = 1
Answer:
UV=29
Step-by-step explanation:
In right triangles AQB and AVB,
∠AQB = ∠AVB ...(i) {Right angles}
∠QBA = ∠VBA ...(ii) {Given that they are equal}
We know that sum of all three angles in a triangle is equal to 180 degree. So wee can write sum equation for each triangle
∠AQB+∠QBA+∠BAQ=180 ...(iii)
∠AVB+∠VBA+∠BAV=180 ...(iv)
using (iii) and (iv)
∠AQB+∠QBA+∠BAQ=∠AVB+∠VBA+∠BAV
∠AVB+∠VBA+∠BAQ=∠AVB+∠VBA+∠BAV (using (i) and (ii))
∠BAQ=∠BAV...(v)
Now consider triangles AQB and AVB;
∠BAQ=∠BAV {from (v)}
∠QBA = ∠VBA {from (ii)}
AB=AB {common side}
So using ASA, triangles AQB and AVB are congruent.
We know that corresponding sides of congruent triangles are equal.
Hence
AQ=AV
5x+9=7x+1
9-1=7x-5x
8=2x
divide both sides by 2
4=x
Now plug value of x=4 into UV=7x+1
UV=7*4+1=28+1=29
<u>Hence UV=29 is final answer.</u>
we know that
step 1
multiply
by 
so

step 2
Divide numerator and denominator by 

therefore
the answer is

Answer:
5/9
Step-by-step explanation: