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3 years ago

Please answer this multiple choice question CORRECTLY for 30 points and brainliest!!

Mathematics

1 answer:

JulijaS [17]3 years ago

4 0

Solve the inequality for x:

5x - 3 ≤ 7x +7

Subtract 7x from each side:

-2x -3 ≤ 7

Add 3 to each side:

-2x ≤ 10

Divide both sides by -2, also when dividing both sides of an inequality you flip the direction of the inequality sign:

x ≥ -5

The dot will be on -5, because the inequality includes equal to, the dot is solid and is greater than, the arrow will point to the right.

The correct answer is D.

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At Joyce's school, tickets for a concert were sold at the rate of 40 per half hour. How many tickets were sold in 7 hours

erik [133]

170 tickets were sold

6 0

3 years ago

Read 2 more answers

A football team loses 15 yards on one play and gains 9 yards on another play. How many total yards did the team lose?

Licemer1 [7]

Answer:

-6

Step-by-step explanation:

imagine you're on a line graph you start at zero and then go backward 15 spaces and move forward 9 spaces where does that leave you

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3 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago

At the beginning of October, you have $300 in your bank account. You get $25 of allowance each week. Your cousin has $200 in her

lys-0071 [83]

Answer:

20 weeks to have the same amount for both bank accounts

Step-by-step explanation:

brainliest plss?

6 0

2 years ago

Differentiate x^(-3)/3-2x^2-x^(-1)

GaryK [48]

Answer:

-2x^2

Step-by-step explanation:

Simplify

x^-1 - 2x^2 - x^-1

becomes

-2x^2

4 0

3 years ago