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Zina [86]
3 years ago
8

Can someone answer this?

Mathematics
1 answer:
kolezko [41]3 years ago
3 0
The correct answer is A.

For y=x, the slope is 1, meaning that as x increments by 1, y also increments by 1.
Using this logic, we know that the graph goes up looking from left to right.

If both ends were to point up or down it would resemble more of a quadratic (parabola).
You might be interested in
Graph the function f(x)=(x+1)(x-2)
creativ13 [48]
F(x) = (x + 1)(x - 2)
f(x) = x(x - 2) + 1(x - 2)
f(x) = x(x) - x(2) + 1(x) - 1(2)
f(x) = x² - 2x + x - 2
f(x) = x² - x - 2

6 0
3 years ago
Find the output for each input of y = -2x.
Bezzdna [24]
Its the first one because -3(-2)=6, 1(-2)=-2, 2(-2)=4 are all correct 

3 0
3 years ago
Read 2 more answers
-1xf(-8)-4xg(4) pls help
KATRIN_1 [288]

Answer:

8f-16g

Step-by-step explanation:

-1×f(-8) -4×g(4)

-1×-8f -4×4g

8f -16g

Hopes this helps

pls mark brainliest

3 0
1 year ago
Read 2 more answers
John is at a local bait shop; he wants to buy bait for his fishing trip. At the store, they are selling live bait for $12 a poun
galina1969 [7]

Answer:

x\geq3

12x+7y\leq63

y\geq0

Step-by-step explanation:

If we let x be the amount of live bait and y be the amount of natural bait, Then we can come up with the following inequalities;

We are told that John would like to get at least 3 pounds of live bait. At least 3 means 3 or more. Since x represents the amount of live bait, we have;

x\geq3

Moreover,we are informed that;

The store sells live bait for $12 a pound and natural bait for $7 a pound. x pounds of live bait would cost 12x while y pounds of natural bait would cost 7y. The total cost would thus be;

12x + 7y

but John only has a budget of $63. This implies that he can spend $63 at most, thus;

12x+7y\leq63

Finally we can have our last inequality as;

y\geq0

8 0
3 years ago
Someone help please
Alla [95]

Answer:  Choice A

\tan(\alpha)*\cot^2(\alpha)\\\\

============================================================

Explanation:

Recall that \tan(x) = \frac{\sin(x)}{\cos(x)} and \cot(x) = \frac{\cos(x)}{\sin(x)}. The connection between tangent and cotangent is simply involving the reciprocal

From this, we can say,

\tan(\alpha)*\cot^2(\alpha)\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\left(\frac{\cos(\alpha)}{\sin(\alpha)}\right)^2\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\frac{\cos^2(\alpha)}{\sin^2(\alpha)}\\\\\\\frac{\sin(\alpha)*\cos^2(\alpha)}{\cos(\alpha)*\sin^2(\alpha)}\\\\\\\frac{\cos^2(\alpha)}{\cos(\alpha)*\sin(\alpha)}\\\\\\\frac{\cos(\alpha)}{\sin(\alpha)}\\\\

In the second to last step, a pair of sine terms cancel. In the last step, a pair of cosine terms cancel.

All of this shows why \tan(\alpha)*\cot^2(\alpha)\\\\ is identical to \frac{\cos(\alpha)}{\sin(\alpha)}\\\\

Therefore, \tan(\alpha)*\cot^2(\alpha)=\frac{\cos(\alpha)}{\sin(\alpha)}\\\\ is an identity. In mathematics, an identity is when both sides are the same thing for any allowed input in the domain.

You can visually confirm that \tan(\alpha)*\cot^2(\alpha)\\\\ is the same as \frac{\cos(\alpha)}{\sin(\alpha)}\\\\ by graphing each function (use x instead of alpha). You should note that both curves use the exact same set of points to form them. In other words, one curve is perfectly on top of the other. I recommend making the curves different colors so you can distinguish them a bit better.

6 0
3 years ago
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