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3 years ago

Kenneth drove 174.2 miles in 3 7/20 hours. What was his average speed?

Mathematics

1 answer:

boyakko [2]3 years ago

8 0

Kenneth's average speed is 55 miles per hour.

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(05.01 MC)

algol13

For the table, y = 9x.

so the price of a short cake is $9

For the graph, y = 4x
so the price of a sweet bread is $4

9-4 = 5

the short cake is $5 more than the sweet bread

5 0

3 years ago

Read 2 more answers

Help<br><br> (5a-3a^3)*(4a-1)

ivann1987 [24]

Answer:

$-12a^{4} + 3a^{3} + 20a^{2} -5a$

Step-by-step explanation:

$(5a-3a^{3} )$ • $(4a-1)$

Let's use FOIL (first, outer, inner, last) to solve this. We'll multiply the terms by one another in that fashion.

$20a^{2} - 5a - 12a^{4} + 3a^{3}$

Rearrange in decreasing exponents.

$-12a^{4} + 3a^{3} + 20a^{2} -5a$

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3 years ago

Plz plz hurry plz hurry plz hurry

e-lub [12.9K]

The answer is C that can be the x-intercepts of the parabola

6 0

2 years ago

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Michael is riding his bicycle a distance of 2.5 miles to Jason's house. He has ridden 1.7 miles so far. If d = the distance in m

lesya692 [45]

The answer I believe would be c.

3 0

3 years ago

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A random sample has been selected from a population. The point estimate = 78.65 and margin of error E = 8.24 for a 90% confidenc

fiasKO [112]

Answer:

90% confidence interval: (70.41,86.89)

Step-by-step explanation:

We are given the following in the question:

Point estimate = 78.65

Margin of error, E = 8.24

Confidence level = 90%

Significance level = 10%

Formula:

$\text{Point estimate} \pm \text{Margin of error}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.10} = \pm 1.64$

$78.65 \pm 8.24 = (70.41,86.89)$

(70.41,86.89) is the required 90% confidence interval.

5 0

3 years ago