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gogolik [260]
3 years ago
5

A bag contains two red marbles, four green ones, one lavender one, four yellows, and six orange marbles. HINT [See Example 7.] H

ow many sets of four marbles include one of each color other than lavender
Mathematics
1 answer:
Rama09 [41]3 years ago
6 0

Answer:

192

Step-by-step explanation:

There are a total of 15 marbles . When the lavender is left out 14 remain.

Using combinations we find that each of the four color marbles can be chosen in the following way.

2C1*4C1*4C1*6C1= 2*4*4*6=  192

We select  one of the two red marbles , one of the four green marbles, one of the four yellow marbles, one of the 6 orange marbles leaving the lavender out.. We apply combinations and then multiply to get the answer.

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A company manufactures a 14-ounce box of cereal. Boxes are randomly weighed to ensure the correct amount. If the discrepancy in
Stolb23 [73]

Answer:

Answer is B on Edge

F(x)=14-x

Step-by-step explanation:

8 0
3 years ago
Use the number line​ below, where RS=5y+5​, ST=2y+5, and RT=52. a. What is the value of​ y? b. Find RS and ST.
Alchen [17]

Answer:

y = 6, RS = 35 and ST = 17

Step-by-step explanation:

Given that,

RS = 5y+5

ST = 2y+5

RT = 52

If we consider a number line,

RT = RS + ST

52 = 5y+5 + 2y+5

52 = 7y + 10

7y = 52-10

7y = 42

y = 6

RS = 5y+5

= 5(6)+5

= 35

ST = 2y+5

= 2(6) +5

= 17

Hence, this is the required solution.

3 0
3 years ago
A circle is growing so that the radius is increasing at the rate of 3 cm/min. How fast is the area of the circle changing at the
Naya [18.7K]

Answer:

The area is growing at a rate of \frac{dA}{dt} =226.2 \,\frac{cm^2}{min}

Step-by-step explanation:

<em>Notice that this problem requires the use of implicit differentiation in related rates (some some calculus concepts to be understood), and not all middle school students cover such.</em>

We identify that the info given on the increasing rate of the circle's radius is 3 \frac{cm}{min} and we identify such as the following differential rate:

\frac{dr}{dt} = 3\,\frac{cm}{min}

Our unknown is the rate at which the area (A) of the circle is growing under these circumstances,that is, we need to find  \frac{dA}{dt}.

So we look into a formula for the area (A) of a circle in terms of its radius (r), so as to have a way of connecting both quantities (A and r):

A=\pi\,r^2

We now apply the derivative operator with respect to time (\frac{d}{dt}) to this equation, and use chain rule as we find the quadratic form of the radius:

\frac{d}{dt} [A=\pi\,r^2]\\\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}

Now we replace the known values of the rate at which the radius is growing ( \frac{dr}{dt} = 3\,\frac{cm}{min}), and also the value of the radius (r = 12 cm) at which we need to find he specific rate of change for the area :

\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}\\\frac{dA}{dt} =\pi\,*2*(12\,cm)*(3\,\frac{cm}{min}) \\\frac{dA}{dt} =226.19467 \,\frac{cm^2}{min}\\

which we can round to one decimal place as:

\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}

4 0
3 years ago
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