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likoan [24]
2 years ago
12

Help!!!!!! 15 Points!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Pie2 years ago
5 0
Cos-1(2/5)= 66.4 degrees
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Need help anyone please!!!
Jobisdone [24]
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8 0
2 years ago
Find the perimeter and the area of the figure. A right-angled trapezoid has a shorter base of 7 centimeters, longer base of 9.5
laila [671]

The given dimensions of 9.5, 6, 7, and 6.5 cm gives the following

perimeter and area of the trapezium.

  • Perimeter: <u>29 cm</u>
  • Area: <u>49.5 cm²</u>

<h3>How can the area and perimeter of the trapezium be found?</h3>

The perimeter of a trapezoid is given as follows;

Perimeter = The sum of the lengths of the sides

Which gives;

Perimeter = 6 + 7 + 6.5 + 9.5 = 29

The perimeter of the trapezoid =<u> 29 cm</u>

  • Perimeter: 29 cm

The area of the trapezoid is given as follows;

Area = \mathbf{ \dfrac{Sum \ of \ the \ parallel \ sides }{2} \times Height}

Which gives;

Area = \dfrac{7 + 9.5 }{2} \times 6 = 49.5

The area of the trapezoid = 49.5 cm²

  • Area:<u> 49.5 cm²</u>

Learn more about the area and perimeter of geometric shapes here:

brainly.com/question/359059

brainly.com/question/11461461

8 0
2 years ago
Connecticut families were asked how much they spent weekly on groceries. Using the following data, construct and interpret a 95%
Amanda [17]

Answer:

The 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

Step-by-step explanation:

The data for the amount of money spent weekly on groceries is as follows:

S = {210, 23, 350, 112, 27, 175, 275, 50, 95, 450}

<em>n</em> = 10

Compute the sample mean and sample standard deviation:

\bar x =\frac{1}{n}\cdot\sum X=\frac{ 1767 }{ 10 }= 176.7

s= \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 188448.1 }{ 10 - 1} } \approx 144.702

It is assumed that the data come from a normal distribution.

Since the population standard deviation is not known, use a <em>t</em> confidence interval.

The critical value of <em>t</em> for 95% confidence level and degrees of freedom = n - 1 = 10 - 1 = 9 is:

t_{\alpha/2, (n-1)}=t_{0.05/2, (10-1)}=t_{0.025, 9}=2.262

*Use a <em>t</em>-table.

Compute the 95% confidence interval for the population mean amount spent on groceries by Connecticut families as follows:

CI=\bar x\pm t_{\alpha/2, (n-1)}\cdot\ \frac{s}{\sqrt{n}}

     =176.7\pm 2.262\cdot\ \frac{144.702}{\sqrt{10}}\\\\=176.7\pm 103.5064\\\\=(73.1936, 280.2064)\\\\\approx (73.20, 280.21)

Thus, the 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

7 0
3 years ago
A number is chosen at random from 1 to 25 find the probability of selecting a number less than 4​
stira [4]

3/25 I hope I helped

7 0
3 years ago
Read 2 more answers
Help Please!!! Giving 30 points!
olga55 [171]

Answer:

1225

Step-by-step explanation:

i just multiplied them together umm yeah...

8 0
2 years ago
Read 2 more answers
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