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3 years ago

A slice is made parallel to the base of a right rectangular pyramid, as shown.

Mathematics

2 answers:

Anettt [7]3 years ago

7 0

Answer:

5 in^2

Step-by-step explanation:

Andrej [43]3 years ago

4 0

The answer is 5 I just took the test

You were supposed to find the area of the darkened area

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I need help plzzz this is algebra

SpyIntel [72]

Set like terms on each side by adding six to the first side and subtracting 1/2x from the first side. this gives you 9<1.5x. divide both sides by 1.5 to get 66. the answer is 4) x>6

3 0

3 years ago

Lakeisha has 3 5/8 yards of fabric. She wants to make a dress that requires 2 1/2 yards of fabric. How much fabric will she have

mezya [45]

1/2 = 4/8

3 5/8 - 2 4/8 = 1 1/8 yards left over

4 0

3 years ago

Read 2 more answers

Can someone pls help me out

Vika [28.1K]

A is the answer I think

3 0

3 years ago

HELP ME!!! 4- 5/8 =?

BlackZzzverrR [31]

Answer:

27/8

Step-by-step explanation:

1.) 4-5/8

Convert element to fraction

2.) 4 x 8/8-5/8

3.) 4 x 8-5/8

4.) 27/8

7 0

2 years ago

On the 1st January 2014 Carol invested some money in a bank account.

Ghella [55]

Answer:

$\large \boxed{\text{\pounds 23 360.00}}$

Step-by-step explanation:

The formula for the accrued amount from compound interest is

$A = P \left(1 + \dfrac{r}{n}\right)^{nt}$

1. Amount in account on 1 Jan 2015

(a) Data:

a = £23 517.60

r = 2.5 %

n = 1

t = 1 yr

(b) Calculations:

r = 0.025

$\begin{array}{rcl}23517.60 & = & P\left (1 + \dfrac{r}{n}\right)^{nt}\\\\& = & P\left (1 + \dfrac{0.025}{1}\right)^{1\times1}\\\\& = & P (1 + 0.025)\\ & = & 1.025 P\\P & = & \dfrac{23517.60 }{1.025} \\\\& = & 22 944.00 \\\end{array}$

The amount that gathered interest was £22 944.00 but, before the interest started accruing, Carol had withdrawn £1000 from the account.

She must have had £23 944 in her account on 1 Jan 2015.

(2) Amount originally invested

(a) Data

A = £23 944.00

$\begin{array}{rcl}23 944.00 & = & 1.025 P\\P & = & \dfrac{23 944.00 }{1.025} \\\\& = & \mathbf{23 360.00} \\\end{array}\\\text{Carol originally invested $\large \boxed{\textbf{\pounds23 360.00}}$ in her account.}$

3. Summary

1 Jan 2014 P = £23 360.00

1 Jan 2015 A = 23 944.00

Withdrawal = <u> -1 000.00 </u>

P = 22 944.00

1 Jan 2016 A = £23 517.60

5 0

3 years ago