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levacccp [35]
3 years ago
15

A seal went 25 feet below sea level to catch a fish. A sea lion dove 10 feet less than three times as deep as the seal to catch

a larger fish. What is the sea lion's position in relation to sea level?
Mathematics
2 answers:
vfiekz [6]3 years ago
7 0

Answer:

65 feet below sea level.

Step-by-step explanation:

With the information provided, we can create the following equation for the position of the sea lion (p)

p = 3x - 10

In this equation, x would be the final position of the seal when it caught the fish. Since we are told that the seal's position is 25 feet below sea level then we can plug in this value as x and solve for p...

p = (3 * 25) - 10

p = 75 - 10

p = 65

Finally, we can see that the sea lion's position is 65 feet below sea level.

Ivanshal [37]3 years ago
5 0

Answer: 3(–25) – (–10)

Step-by-step explanation:   Answer on Edge...

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2 years ago
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alina1380 [7]

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Step-by-step explanation:

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After painting the fence steve and janet realize that their house also needs painting. But steve will have to do the painting hi
gladu [14]

Answer:

Therefore, Steve will paint house for 20.6 days.

Step-by-step explanation:

We know that Steve determines that it would take them 9 days to paint the house together (if they were both healthy) and that it would take Janet (when healthy) 16 days to paint the house alone.

We conclude that in 1 day Janet painted 1/16 of the house. In nine days, Janet painted 9/16 of house.

So, 7/16 of house paint Steve in nine days.

We have the following proportion:

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4 0
3 years ago
Use synthetic division to solve (x^3+1)/(x-1). What is the quotient?
Sav [38]

Answer:

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Step-by-step explanation:

See below for the tableau. The quotient is x^2 +x +1.

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7 0
3 years ago
The plane continued to descend, but leveled off to an angle of descent of 3° degrees for approximately 2 miles. How many feet di
Alex787 [66]
ANSWER: Plane dropped 6097 feet in altitude.
BECAUSE: An airplane is at point A from where it continued to descend by 30° for an approximate distance of 2 miles
∠ACB = Angle of descent = 30°
Distance BC = 2 miles
Let the plane dropped the altitude = h miles
Now tan 30° =


h = 1.155 miles
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Since 1 mile = 5280 feet
1.15 miles = 5280×1.16 feet
= 6097 feet
Therefore, the plane dropped by 6097 feet vertically.
3 0
3 years ago
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