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levacccp [35]
3 years ago
15

A seal went 25 feet below sea level to catch a fish. A sea lion dove 10 feet less than three times as deep as the seal to catch

a larger fish. What is the sea lion's position in relation to sea level?
Mathematics
2 answers:
vfiekz [6]3 years ago
7 0

Answer:

65 feet below sea level.

Step-by-step explanation:

With the information provided, we can create the following equation for the position of the sea lion (p)

p = 3x - 10

In this equation, x would be the final position of the seal when it caught the fish. Since we are told that the seal's position is 25 feet below sea level then we can plug in this value as x and solve for p...

p = (3 * 25) - 10

p = 75 - 10

p = 65

Finally, we can see that the sea lion's position is 65 feet below sea level.

Ivanshal [37]3 years ago
5 0

Answer: 3(–25) – (–10)

Step-by-step explanation:   Answer on Edge...

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Answer:

This is simple linear regression analysis. We can determine the line of best fit using technology

Step-by-step explanation:

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Which inequality is graphed on the number line? please Hurry!!!
user100 [1]

Answer:

Option C

Step-by-step explanation:

From the number line given in the picture,

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3 0
3 years ago
Solve for x <br>x/3 = 5/8​
dlinn [17]

Answer:

x = 15/8

Step-by-step explanation:

x/3 = 5/8

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Divide each side by 8

8x/8 = 15/8

x = 15/8

3 0
3 years ago
Read 2 more answers
Help! If you know this can you tell me how to do it?
aleksandr82 [10.1K]

Answer:

c

Step-by-step explanation:

Here's how this works:

Get everything together into one fraction by finding the LCD and doing the math.  The LCD is sin(x) cos(x).  Multiplying that in to each term looks like this:

[sin(x)cos(x)]\frac{sin(x)}{cos(x)}+[sin(x)cos(x)]\frac{cos(x)}{sin(x)} =?

In the first term, the cos(x)'s cancel out, and in the second term the sin(x)'s cancel out, leaving:

\frac{sin^2(x)}{sin(x)cos(x)}+\frac{cos^2(x)}{sin(x)cos(x)}=?

Put everything over the common denominator now:

\frac{sin^2(x)+cos^2(x)}{sin(x)cos(x)}=?

Since sin^2(x)+cos^2(x)=1, we will make that substitution:

\frac{1}{sin(x)cos(x)}

We could separate that fraction into 2:

\frac{1}{sin(x)}×\frac{1}{cos(x)}

\frac{1}{sin(x)}=csc(x)  and  \frac{1}{cos(x)}=sec(x)

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5 0
3 years ago
Let X denote the time in minutes (rounded to the nearest half minute) for a blood sample to be taken. The probability mass funct
Basile [38]

This question is incomplete, the complete question is;

Let X denote the time in minutes (rounded to the nearest half minute) for a blood sample to be taken. The probability mass function for X is:

x     0       0.5       1       1.5       2       2.5

f(x)  0.1     0.2     0.3    0.2     0.1       0.1

determine;

a) P( X < 2.5 )

B) P( 0.75 < X ≤ 1.5 )

Answer:

a) P( X < 2.5 ) = 0.9

b) P( 0.75 < X ≤ 1.5 ) = 0.5

Step-by-step explanation:

Given the data in the question;

The probability mass function for X is:

x     0       0.5       1       1.5       2       2.5

f(x)  0.1     0.2     0.3    0.2     0.1       0.1

a) P( X < 2.5 )

P( X < 2.5 ) = p[ x = 0 ] + p[ x = 0.5 ] + p[ x = 1 ] + p[ x = 1.5 ] + p[ x = 2 ]

so

P( X < 2.5 ) = 0.1 + 0.2 + 0.3 + 0.2 + 0.1

P( X < 2.5 ) = 0.9

b) P( 0.75 < X ≤ 1.5 )

P( 0.75 < X ≤ 1.5 ) = p[ x = 1 ] + p[ x = 1.5 ]

so

P( 0.75 < X ≤ 1.5 ) = 0.3 + 0.2

P( 0.75 < X ≤ 1.5 ) = 0.5

3 0
3 years ago
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