The end result of increased molecular motion is that the object expands and takes up more space. {I don’t know if it’s right, I‘m just trying to help}
Answer:
f(x) = 6x²-3
f(x) = 0
6x²-3 = 0
6x² = 3
x² = 3/6
x² = 1/2
x = 1/√2 , -1/√2
Roots of f(x) = 1/√2 , -1/√2
Verification = (i) 6(1/√2)² - 3
= 6(1/2) - 3
= 3-3
= 0
(ii) 6(-1/√2)² - 3
= 6(1/2) - 3
= 3-3
= 0
47% yield.
First, let's determine how many moles of ethane was used and how many moles of CO2 produced. Start with the respective atomic weights.
Atomic weight carbon = 12.0107
Atomic weight hydrogen = 1.00794
Atomic weight oxygen = 15.999
Molar mass C2H6 = 2 * 12.0107 + 6 * 1.00794 = 30.06904 g/mol
Molar mass CO2 = 12.0107 + 2 * 15.999 = 44.0087 g/mol
Moles C2H6 = 8 g / 30.06904 g/mol = 0.266054387 mol
Moles CO2 = 11 g / 44.0087 g/mol = 0.249950578 mol
Looking at the balanced equation, for every 2 moles of C2H6 consumed, 4 moles of CO2 should be produced. So at 100% yield, we should have 0.266054387 / 2 * 4 = 0.532108774 moles of CO2. But we only have 0.249950578 moles, or 0.249950578 / 0.532108774 = 0.46973587 =
46.973587% of what was expected.
Rounding to 2 significant figures gives 47% yield.
The glass capillary having one end closed and one open end is generally used for the determination of melting point of the sample. From the open end, the sample is put into the capillary, the sample must be firmly packed as the melting point is an intrinsic property that means it is independent of sample size. So, in order to determine the melting point of the sample small sample in the capillary is sufficient to measure the melting point of the sample. To obtain the more consistent value of melting point one must pack the sample firmly in the capillary.
Hence, when determining the melting point of a substance, one should use a small sample in the capillary and the sample should be firmly packed.
Answer:
We can see the bright matter, like stars, but we know some other matter is there(dark matter)because of how it pulls on the bright matter.
Explanation:
