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uranmaximum [27]
2 years ago
9

The limiting reactant is the chemical substance that determines the amount of product(s) that can ultimately be formed in a reac

tion. During the reaction, the limiting reactant is completely consumed or used up, and therefore, causes the reaction to stop. The limiting reactant can be identified through stoichiometric calculations. After comparing the results, the reactant that produces the smaller mass of product is identified as the limiting reactant. Determine the limiting reactant and calculate the number of grams of Al2O3 that can be formed when 10.0 grams of Al and 5.00 grams of O2 react. 4 Al(s) + 3 O2(g) → 2 Al2O3(s) For the calculations in this module, the molar mass of an element will be rounded to the hundredths place (0.01 g).
Chemistry
1 answer:
Mariulka [41]2 years ago
6 0

Explanation:

Al=10,o2=5

(Al10)2(o5)3

The answer is oxygen.

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Answer : The correct expression will be:

K=(K_1)^2\times K_2

Explanation :

The chemical reactions are :

(1) \frac{1}{2}N_2(g)+\frac{1}{2}O_2(g)\rightleftharpoons NO(g) K_1

(2) 2NO(g)+O_2(g)\rightleftharpoons N_2O_4(g) K_2

The final chemical reaction is :

N_2(g)+2O_2(g)\rightleftharpoons N_2O_4 K=?

Now we have to calculate the value of K for the final reaction.

Now equation 1 is multiply by 2 and then add both the reaction we get the value of 'K'.

If the equation is multiplied by a factor of '2', the equilibrium constant will be the square of the equilibrium constant of initial reaction.

If the two equations are added then equilibrium constant will be multiplied.

Thus, the value of 'K' will be:

K=(K_1)^2\times K_2

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Explanation:

Cyclic quadrilaterals are the special group of quadrilaterals with all its base lying on the circumference of the circle. In other words, a quadrilateral inscribed in a circle is called a cyclic quadrilateral.

Cyclic quadrilateral are characterised by some special features such as

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Using the property 1  

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