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Art [367]
3 years ago
8

What information do we need to determine the molecular formula of a compound from the empirical formula?

Chemistry
1 answer:
defon3 years ago
6 0

Answer:

Molecular mass

Explanation:

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,  

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Thus if the molecular mass is known, then we can find the value of n which results to molecular formula.

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A salt wedge forms in an estuary because
kherson [118]

Answer:

a rapidly flowing river discharges into the ocean where tidal currents are weak.

Explanation:

The force of the river pushing fresh water out to sea rather than tidal currents transporting seawater upstream determines the water circulation in these estuaries.

6 0
3 years ago
Without using Appendix B, predict the sign of ΔS° for(b) KBr(s)→ KBr(aq)
Volgvan

Since the sign is positive, the entropy increased by 88.48 J/K.

Examine the phases of the species present to determine whether a physical or chemical process will cause an increase or decrease in entropy. Keep in mind "Silly Little Goats" to aid you in telling.

[1 Sf K+1 + 1 Sf Br-1 (aq)] ([1Sf(KBr (s))])

[1(102.5) + 1(82.42)] - [1(96.44)] = 88.48 J/K

If the entropy has grown, we say that Delta S is positive, and if it has dropped, we say that Delta S is negative. Due to its ionic nature, KBr is soluble in water and causes the 'K(+)' ions to hydrate.

Learn more about Entropy here-

brainly.com/question/13146879

#SPJ4

8 0
2 years ago
11.
tatiyna
D. dishwashing Soap/Liquid
7 0
3 years ago
PLEASE ANSWER ASAP I WILL GIVE BRAINLIEST!!
anzhelika [568]
It’s lower, hope this helps with your issue and helps solve your problem, no problem
5 0
3 years ago
Read 2 more answers
Calculate the specific heat of the substance if 373 J is required to raise the temperature of a 312 gram sample by 25°C?
I am Lyosha [343]

Explanation:

Q = 373J

∆∅ = 25°C

m = 312g

c = x

Q = mc∆∅

373 = 312(x)(25)

373 = 7800x

x = 373/7800

x = 0.0478J/(g°C)

4 0
3 years ago
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