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Art [367]
4 years ago
8

What information do we need to determine the molecular formula of a compound from the empirical formula?

Chemistry
1 answer:
defon4 years ago
6 0

Answer:

Molecular mass

Explanation:

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,  

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Thus if the molecular mass is known, then we can find the value of n which results to molecular formula.

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Check my answer plz!! 100 points. Tell me if they are wrong! 1. You have three elements, A, B, and C, with the following electro
Artyom0805 [142]

look good w small changes below:

Answer:  


AB is an ionic compound. The electronegativity difference between A and B is greater.  


AC is an ionic compound. The electronegativity difference between A and C is greater.  


BC is a covalent compound because the electronegativity difference between C and B is small.


everything else look good!

6 0
3 years ago
Read 2 more answers
The density of mercury is 13.6 g/mL What is the mass in kilograms of 5L of mercury?
Oliga [24]

Answer:

68kg

Explanation:

density= mass÷volume

5 0
4 years ago
An object weighing 90 n has a volume of 45 ml and a mass of 9.0 g what is its density
UNO [17]
D= mass over volume

So, density equals 9.0g divided by 45ml.

SO, D=.25 g/ml

I'm not 100% sure this is correct, though. Best if luck. ♡
7 0
4 years ago
Which nitrogen-containing base is found only in rna?
bija089 [108]
The answer to this is Codon. 
3 0
4 years ago
Ethanol melts at -114 degree C. The enthalpy of fusion
Brut [27]

Answer: The heat required is 6.88 kJ.

Explanation:

The conversions involved in this process are :

(1):ethanol(s)(-135^0C)\rightarrow ethanol(s)(-114^0C)\\\\(2):ethanol(s)(-114^0C)\rightarrow ethanol(l)(-114^0C)\\\\(3):ethanol(l)(-114^0C)\rightarrow ethanol(l)(-50^0C)

Now we have to calculate the enthalpy change.

\Delta H=[m\times c_{p,s}\times (T_{final}-T_{initial})]+n\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]+n\times \Delta H_{vap}+[m\times c_{p,g}\times (T_{final}-T_{initial})]

where,

\Delta H = enthalpy change = ?

m = mass of ethanol = 25.0 g

c_{p,s} = specific heat of solid ethanol= 0.97 J/gK

c_{p,l} = specific heat of liquid ethanol = 2.31 J/gK

n = number of moles of ethanol = \frac{\text{Mass of ethanol}}{\text{Molar mass of ethanol}}=\frac{25.0g}{46g/mole}=0.543mole

\Delta H_{fusion} = enthalpy change for fusion = 5.02 KJ/mole = 5020 J/mole

T_{final}-T_{initial}=\Delta T = change in temperature

The value of change in temperature always same in Kelvin and degree Celsius.

Now put all the given values in the above expression, we get

\Delta H=[25.0 g\times 0.97J/gK\times (-114-(-135)K]+0.534mole\times 5020J/mole+[25.0g\times 2.31J/gK\times (-50-(-114))K]

\Delta H=6885.93J=6.88kJ     (1 KJ = 1000 J)

Therefore, the heat required is 6.88 kJ

3 0
3 years ago
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