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Andrew [12]
3 years ago
15

What is the solution to –4(8 – 3x) ≥ 6x – 8?

Mathematics
1 answer:
melisa1 [442]3 years ago
8 0
-4(8-3x)≥6x-8
Expand the left side.
-32+12x≥6x-8
Add 32 to both sides
12x≥6x+24
Subtract 6x.
6x≥24
Divide both sides by 6.
x≥4

Answer: x ≥ 4
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Use the distributive property to find the price. 5($5.91) a. $30.45 b. $29.55 c. $25.50
enot [183]

5*5 = 25

5*9= 45

5*1= 5

25 dollars now add the cents

now it is $25.50

6 0
3 years ago
Read 2 more answers
What is the slope of the graph?
VMariaS [17]

<u>Given</u>:

Given that an aquarium is being filled with water.

The given graph shows the height of the water over time as the aquarium is being filled.

We need to determine the slope of the graph.

<u>Slope</u>:

The slope of the given graph can be determined using the formula,

m=\frac{y_2-y_1}{x_2-x_1}

Since, the slope is same for all the points on the straight line, then let us consider the points (2,5) and (4,10)

Substituting these points in the above formula, we get;

m=\frac{10-5}{4-2}

Simplifying, we get;

m=\frac{5}{2}

m=2.5

Thus, the slope of the given graph is 2.5

8 0
3 years ago
What do I get if I divide 1 by 5/13 as an improper fraction​
Tasya [4]

Answer:

15/13

Step-by-step explanation:

hope that helps thanks for ur questions

4 0
2 years ago
The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
SCORPION-xisa [38]

Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

5 0
3 years ago
Please help and show work!!
Advocard [28]

1/3x + y = -2

-1/3x         -1/3x

y = -1/3x-2

4 0
3 years ago
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