Question

Help Asap! I have 30 minutes! 30 Points!

Answer 1

(2x - 5) (5x - 10)
Use FOIL
10x² - 20x - 25x + 50

10x²  - 45x + 50
 

5( 2x² - 9x + 10)

     2x           -5 
      x             -2

5(2x - 5)(x -2)

make each equal to 0
2x - 5 = 0
x - 2 = 0

2x - 5 = 0                        x - 2 = 0
2x - 5 (+5) = 0                x - 2 (+2) = 0 (+2)
2x = 5                             x  = 2
x = 5/2

x = 5/2 , 2

hope this helps

Answer 2

Help Asap! I have 30 minutes! 30 Points!
What is the value of x? (2x - 5) (5x - 10)
(No answers, you have to write the answers)

$(2x-5)(5x-10)= 0 \\ \\ the\ distributive\ property. \\ \\ 10x^2-20x-25x+50 = 0 \\ \\ 10x^2-45x +50 = 0 \\ \\ Bhaskara \to \ x _{1\ and\ 2} = \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} \quad a=10\quad b= -45\quad c=50 \\ \\ \\ \ x _{1\ and\ 2} = \dfrac{-(-45)\pm \sqrt{(45)^2-4(10)(50)} }{2(10)} \\ \\ \\\ x _{1\ and\ 2} = \dfrac{+45\pm \sqrt{2025-2000} }{20} \\ \\ \\\ x _{1\ and\ 2} = \dfrac{+45\pm \sqrt{25} }{20}$

$x _{1\ and\ 2} = \dfrac{+45\pm 5 }{20} \\ \\ \\ x _{1} = \dfrac{+45+ 5 }{20} \qquad\qquad x _{2} = \dfrac{+45-5 }{20}\\ \\ \\ x _{1} = \dfrac{50 }{20} \qquad\qquad \qquad x _{2} = \dfrac{+40 }{20}\\ \\ \\ x _{1} = \dfrac{5 }{2} \qquad\qquad \qquad x _{2} = \dfrac{+4 }{2} \\ \\ \\ \boxed{\\ \\ \\ x _{1} = \dfrac{5 }{2} \qquad\qquad \qquad x _{2} = 2}$


I wish you much success in your studies!!!!