All categories

3 years ago

Reducing your carbon footprint has no effect on carbon emissions. a. True b. False

2 answers:

8 0

The answer is false.
Reducing carbon footprint has no effect on carbon emissions. Carbon emission is reduced by lower carbon footprints. As you read national geographic,China and USA are doing nothing to help. Instead, china tripled their coal used recently.

mihalych1998 [28]3 years ago

6 0

Answer: FALSE

Explanation:

this answer is tested, i answered false on my quiz and was right

You might be interested in

8. Create two imaginary organisms found in the same ecosystem that share a

11111nata11111 [884]

Answer:

Glorks are symbiotic bacteria in Spagoodles. The ecosystem is a hot volcanic one with barely edible lava grass that grows. The Glorks get a place to stay in the intenstines of the Spagoodles, while the Spagoodles get better digestions from the Glorks breaking down lava grass.

Explanation:

No need. Just invent something.

3 0

3 years ago

How is the sun’s energy passed along in an ecosystem?

Katen [24]

Answer:

Energy is passed between organisms through the food chain. The organism that obtains energy from sunlight is called the producer.

Explanation:

8 0

3 years ago

What is soil erosion?

Roman55 [17]

Soil erosion is defined as the wearing away of topsoil. Topsoil is the top layer of soil and is the most fertile because it contains the most organic, nutrient-rich materials. Therefore, this is the layer that farmers want to protect for growing their crops and ranchers want to protect for growing grasses for their cattle to graze on.

5 0

3 years ago

Read 2 more answers

What are the the similarities and differences of ovary and ovulation?

Wewaii [24]

Answer:

Ovary is an organ of the female reproductive system which is involved in the production and releasing of an ovum or egg. From the ovaries, the egg is released into the Fallopian tube in the uterus.

Ovulation can be described as the process in which an egg is released from the ovary. It may or may not be fertilized after being released.

Similarities of the ovary and ovulation are that both refer to releasing of the egg.

4 0

3 years ago

Cystic fibrosis (CF) is one of most common recessive disorders among Caucasians it affects 1 in 1,700 newborns. What is the expe

Phantasy [73]

Answer: The expected frequency of carriers is P(Aa)=0.046.

The proportion of childs with CF is P(aa)=0.024.

25% of having a child with CF (aa).

Explanation:

Hardy-Weinberg's principle states that in a large enough population, in which mating occurs randomly and which is not subject to mutation, selection or migration, gene and genotype frequencies remain constant from one generation to the next one, once a state of equilibrium has been reached which in autosomal loci is reached after one generation. So, a population is said to be in balance when the alleles in polymorphic systems maintain their frequency in the population over generations.

Given the gene allele frequencies in the gene pool of a population, it is possible to calculate the expected frequencies of the progeny's genotypes and phenotypes. <u>If P = percentage of the allele A (dominant) and q = percentage of the allele a (recessive)</u>, the checkerboard method can be used to produce all possible random combinations of these gametes.

Note that p + q = 1, that is, the percentages of gametes A and a must equal 100% to include all gametes in the gene pool.

The genotypic frequencies added together should also equal 1 or 100%, and all the equations can be summarized as follows:

$p+q=1\\(p+q)^{2} = p^{2} +2pq+q^{2} = 1\\P(AA)=p^{2} \\P(aa)=q^{2} \\P(Aa)=2pq1$

So, there are 1700 individuals and only one is affected. Since it is a recessive disorder, the genotype of that individual must be aa. So the genotypic frequency of aa is 1/1700=0.000588.

Then, $P(aa)=q^{2}=0.000588$ . And with that we can calculate the value of q,

$P(a)=q=\sqrt{0.000588}=0.024$

And since we know that p+q=1, we can find out the value of p.

$p+0.024=1\\1-0.024=p\\p=0.976$

Next, we find out the genotypic frequency of the genotype AA:

$P(A)=p=0.976\\P(AA)=p^{2} = 0.976^{2}=0.95$

Now, we can find out the genotypic frequency of the genotype Aa:

$P(Aa)=2pq=2 x 0.976 x 0.024 = 0.046$

Notice than:

$p^{2} + 2pq + q^{2} = 1\\x^{2} 0.976^{2} + 2 x 0.976 x 0.024 + 0.024^{2} = 1$

Then, the expected frequency of carriers is P(Aa)=0.046

The proportion of childs with CF is P(aa)=0.024

If two parents are carriers, then their genotypes are Aa.

Gametes produced by them can only have one allele of the gene. So they can either produce A gametes, or a gametes.

In the punnett square, we can see that there genotypic ratio is 2:1:1 and the phenotypic ratio is 3:1. So, there is a probability of 25% of having an unaffected child, with both normal alleles (AA); 50% of having a carrier child (Aa) and 25% (0.25) of having a child with CF (aa).

5 0

3 years ago