Quadratic is in the form
ax^2+bx+c=0
so distribute and stuff and simplify
remember
a(b+c)=ab+ac
(x+2)^2+5(x+2)-6=0
remember order of opertaions
(x+2)(x+2)+5(x+2)-6=0
x^2+4x+4+5x+10-6=0
add like terms
x^2+9x+8=0
3x(2) + 2(2x - 20) = 16 - 2x(2)
6x + 4x - 40 = 16 - 4x
10x - 40 = 16 - 4x
14x - 40 = 16
14x = 56
x = 4
Hope this helps! ;)
Answer:
The expression used to find the change in temperature per hour is Algebraic expression
Thus per hour; the temperature falls at the rate of
Step-by-step explanation:
A temperature falls from 0 to
in 
Which expression finds the change in temperature per hour.
From the above given information;
The initial temperature is 0
The final temperature is
The change in temperature is 


Thus;
-12.25 ° = 3.5 hours
To find the change in x° per hour; we have;
x° = 1 hour
The expression used to find the change in temperature per hour is Algebraic expression
From above if we cross multiply ; we have;
(- 12.25° × 1 hour) = (x° × 3.5 hour)
Divide both sides by 3.5 hours; we have:

x° = - 3.5
x° = 
Thus per hour; the temperature falls at the rate of