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AysviL [449]
3 years ago
6

Rezolvați + explicație plzzzz

Mathematics
1 answer:
almond37 [142]3 years ago
5 0

Follow PEMDAS

anything to the power of 0 is 1

1)32+10=42:1-9=-8

Ask questions if you still need help on the other

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1st wire. 340m

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A data set includes data from student evaluations of courses. The summary statistics are nequals83​, x overbarequals3.32​, sequa
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Answer:

Hypothesis

Null hypothesis:\mu =3.50    

Alternative hypothesis:\mu \neq 3.50    

Statistic

t=\frac{3.32-3.50}{\frac{0.56}{\sqrt{83}}}=-2.928    

P value

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And the p value would be given by:

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Conclusion

Since the p value is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 3.5

Step-by-step explanation:

Information given

\bar X=3.32 represent the sample mean

s=0.56 represent the sample deviation

n=83 sample size    

\mu_o =3.5 represent the value to test

t would represent the statistic

p_v represent the p value

System of hypothesis

We want to verify if the true mean is equal to 3.5, the system of hypothesis are:    

Null hypothesis:\mu =3.50    

Alternative hypothesis:\mu \neq 3.50    

Statistic

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

Replacing we got:

t=\frac{3.32-3.50}{\frac{0.56}{\sqrt{83}}}=-2.928    

P value

The degrees of freedom are given by:

df=n-1=83-1=82

And the p value would be given by:

p_v =2*P(t_{(82)}    

Conclusion

Since the p value is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 3.5

8 0
2 years ago
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