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4 years ago

How l can write a brief summary about measurement for 3rd grade

1 answer:

7 0

The topic "measurement" is very, very broad.
You'd be best off by limiting your scope to a couple of familiar situations:

Weighing a piece of chocolate

Having your height and weight measured by the school nurse

Counting the number of coins in your pocket

Getting a rough measure of how well you have learned new material by checking how many questions you got right out of the whole test.

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Randomly selecting a seventh grader from a school that has 250 sixth graders, 225 seventh graders, and 275 eighth graders

Alla [95]

250 + 225 + 275 = 750 in total so 1/750

5 0

3 years ago

Read 2 more answers

What is the answer to this math problem, g=c+x

barxatty [35]

Step-by-step explanation:

Q: Solve for x

g = c + x

g - c = x

3 0

4 years ago

Rewrite the following polynomial in standard form. - 10 - 9x2 +x

Mademuasel [1]

Answer:

-9x² + x - 10

Step-by-step explanation:

To write in a standart form, variables go in an alphabetical order, from highest to lowest exponent. The last thing to write is a number by itself (ex. 10)

7 0

2 years ago

The radius, r, of a circle is one-half of the length of its diameter, d. r= r= d + r = d 2 r = d r = d

PIT_PIT [208]

If the radius is HALF of the diameter, then the expression would be 1/2r=d or d/2=r.

hope it helps!

8 0

3 years ago

A rectangle, a triangle, and two congruent semicircles were used to form the figure shown. Rectangle 5cm,20cmcircle : radius 5cm

Schach [20]

Answer:

The area of a shape is the amount of space it occupies

Step 1:

We start by calculating the area of the rectangle using:

$\begin{gathered} A_{rectangle}=l\times b \\ \end{gathered}$

By substituting the values, we will have

$\begin{gathered} A_{rectangle}=l\times b \\ A_{rectangle}=20cm\times5cm \\ A_{rectangle}=100cm^2 \\ A_1=100cm^2 \end{gathered}$

Step 2:

we calculate the area of the triangle using:

$A_{triangle}=\frac{1}{2}\times base\times height$

By substituting the values, we will have

$\begin{gathered} A_{tr\imaginaryI angle}=\frac{1}{2}\times base\times he\imaginaryI ght \\ A_{tr\mathrm{i}angle}=\frac{1}{2}\times10cm\times8cm \\ A_{tr\mathrm{i}angle}=\frac{80cm^2}{2} \\ A_{tr\mathrm{i}angle}=40cm^2 \\ A_2=40cm^2 \end{gathered}$

Step 3:

Calculate the area of the two semicircles

$A_{semicircle}=\frac{\pi r^2}{2}$

By substituting the values, we will have

$\begin{gathered} A_{sem\imaginaryI c\imaginaryI rcle}=\frac{\pi r^{2}}{2} \\ A_{sem\mathrm{i}c\mathrm{i}rcle}=3.14\times\frac{5^2}{2} \\ A_{sem\mathrm{i}c\mathrm{i}rcle}=39.25cm^2 \\ Area\text{ of two semicircle will be} \\ A_3=39.25cm^2\times2 \\ A_3=78.5cm^2 \end{gathered}$

Step 4:

Calculate the area of the shape

We will calculate the area of the shape by adding all the individual areas together

$A_{shape}=A_1+A_2+A_3$

By substituting the values, we will have

$\begin{gathered} A_{shape}=A_{1}+A_{2}+A_{3} \\ A_{shape}=100cm^2+40cm^2+78.5cm^2 \\ A_{shape}=218.5cm^3 \end{gathered}$

Hence,

The area of the shape will be

$\Rightarrow218.5cm^2$

4 0

1 year ago