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3 years ago

Which of the following is equal to the rational expression when x does not equal 3 or -10? (x+5)(x-3)/(x-3)(x+10)

1 answer:

7 0

For an expression to have a rational equivalent when solved, the denominator should not be equal to 0. If the denominator is equal to zero, the expression becomes indefinite or undetermined. This is the reason for the restriction of the use of x being equal to 3 or -10.

In the given above, we can see that the expression x-3 appears both in the numerator and denominator. Hence, this can be cancelled. We are then left with the expression,
(x + 5) / (x + 10)

Therefore, the answer to this item is letter C.

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What is the slope for this??

aleksandr82 [10.1K]

Answer:

slope: $\frac{13}{4}$

Step-by-step explanation:

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Which function has an inverse that is a function?

fredd [130]

Answer:

m(x)

Step-by-step explanation:

they would have to pass the horizontal line test and the vertical line test for both the origional and the inverse.

b(x) does not pass the horizontal line test in any of the y values over 3

d(x) does not pass the horizontal line test for y=-9

p(x) does not pass the horizontal line test for positive y values

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3 years ago

A number has the same digit in its hundreds place and its hundredths place.

Yuki888 [10]

Answer:

One is 2 0's before the decimal point (100) and the other is 2 decimal places AFTER the decimal point (0.01)

Essentially, the question is asking us how many times do we multiply 0.01 to get 100? This will be how many times greater 100 is compared to 0.01

Lets move the decimal point 4 times to the right:

0.01

00.1

1.0

10.0

100.0

Step-by-step explanation:

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3 years ago

Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))

Marrrta [24]

Answer:

$\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Step-by-step explanation:

$\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine $\frac{1}{c} + \frac{1}{h}$

$\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine the bottom, too.

$=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}$

Apply the fraction rule

$=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}$

Cancel

$=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Therefore, $\frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

5 0

3 years ago

What is the area of a regular nonagon (9 sides) with side length of 15 cm and apothem of 20.6 cm? Round the answer to the neares

Triss [41]

We know that

<span>The nine radii of a regular Nonagon divides into 9 congruent isosceles triangles
</span>therefore
[the area of <span>a regular nonagon]=9*[area of isosceles triangle]

</span>[area of isosceles triangle]=b*h/2------> 15*20.6/2----> 154.5 cm²
so
[the area of a regular nonagon]=9*[154.5]------> 1390.5 cm²

the answer is
1390.5 cm²

5 0

3 years ago