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vladimir1956 [14]
3 years ago
7

volume of cylinder with radius of base 7cm is 102cm³.what will be the volume of cone having same radius of base and same height​

Mathematics
1 answer:
Amanda [17]3 years ago
4 0

3 I believe the answer

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What is the mean, median, mode, and range of the numbers 8,15,3,6,13,9
ivolga24 [154]

Hello There!

To find the mean, add up all the numbers and divide according to how many numbers there are. The mean for this set would be <em>"9"</em>

<em></em>

To find the median, place the numbers in value order and find the middle. if there is no middle, add up the two numbers in middle and divide by 2. In this set, the median would be <em>"8.5"</em>

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To find the mode or modal value, it is best to put the numbers in order. Then count how many of each number. A number that appears most often is the mode. In this set, there would be no mode.

The range of a set of data is the difference between the highest and lowest values in the set. In this set, the range would be <em>"12"</em>

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3 years ago
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GuDViN [60]
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3 years ago
Shield volcanoes a) resemble a warrior's shield lying on the ground. b) are always active. c) are only found in Iceland.
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Answer:

I dont get it

Step-by-step explanation:

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2 years ago
How do I graph this problem?
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3 years ago
Arrange the equations in the correct sequence to rewrite the formula for displacement, , to find a. In this formula, d is displa
valina [46]
Answer: 

a=2[d-V_0t]/t^2=2d/t^2-2v_0/t

Explanation:


Since, you have not included the formula, I will work here with the formula for constant accelaration motion that relates the four variables: displacement (d), Vo (initial velocity), a (acceleration) and t (time).

1) displacement formula:

d= V_0t+\frac{1}{2} at^2

2) Subtract the term Vot from both sides:

d-V_0t= \frac{1}{2} at^2

3) Multiply both sides by 2:

2d -2V_0t=at^2

4) Divide both sides by t²

2[d-V_0t]/t^2=a

So, you have obtainded:

a = 2[d - Vo×t] / t²

Yet, you can arrange it in different ways. For example, you might separate into two terms:

a =  \frac{2d}{t^2} - \frac{2V_0}{t}

8 0
2 years ago
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