They are not in proportion, since its 6:9 round it down (2:3) so pretend the 6 are apples and the 9 are oranges

Every 2 apples there are 3 oranges

So having 9 apples what is that?

2 x ? = 9

2 x 4.5 = 9

So if you want to keep 2:3 you have you times the oranges by 4.5 aswell!

3 x 4.5 = 13.5

So since it is 9:12 not 9:13.5 they are not in proportion

7 0

3 years ago

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How do u do b??????????

horrorfan [7]

the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.

the input goes to the 1st machine and the output of that goes to the 2nd machine.

if she uses and input of 6 on the 2nd one, the result will be 6² - 6 = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.

clearly we can never get an output of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.

let's check something, we need a -5 on the 2nd, so

$\bf \underset{final~out put}{\stackrel{y}{-5}}=x^2-6\implies 1=x^2\implies \sqrt{1}=x\implies 1=x$

so if we use a "1" as the output on the first machine, we should be able to find out what input we need, let's do that.

$\bf \underset{first~out put}{\stackrel{y}{1}}=\sqrt{x-5}\implies 1^2=x-5\implies 1=x-5\implies 6=x$

so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.

$\bf \stackrel{first~machine}{y=\sqrt{\boxed{6}-5}}\implies y=\sqrt{1}\implies y=1 \\\\\\ \stackrel{second~machine}{y = \boxed{1}^2-6}\implies y = 1-6\implies y = -5$

5 0

3 years ago

HELP MEHHHHHHHHH 4-6

frutty [35]

I'd be glad to help but i don't know the question

6 0

3 years ago

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