we know that
The measure of the external angle is the semidifference of the arcs that it covers
so
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
Let
x------> minor arc MN
major arc MN=360-x
substitute in the formula above
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
75.86=(1/2)*(360-x-x)------> 151.72=(360-2x)------>360-151.72=2x
x=104.14°
therefore
the answer is
the measure of arc MN (minor arc) is 104.14°
Answer:
<em>(4). is the correct answer</em>
Step-by-step explanation:
(- 3, 1, 1)
(1). - 3 - 1 - 1 ≠ - 2 not an answer...
(2). - 3 - 1 + 3(1) ≠ 2 not an answer...
(3). 4( - 3) + 1 - 3(1) ≠ - 4 not an answer...
<em>(4). 2(- 3) + 3(1) + 4(1) = 1 </em>
<em>3(1) + 3(1) = 6 </em>
<em>- 3 = - 3(1) </em>
Step-by-step explanation:
4(x-6)=2
4x-24=2
4x=2+24
4x=28
x=7
Richard and Teo are 7 and 24.
7 times two is 14
24 is ten more than 14
31-7 is 24
49,400-20,000=29400
29400/24=1225 average miles per month
