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4 years ago

A right triangle has side lengths 7, 24, and 25 as shown below.

Mathematics

1 answer:

Hoochie [10]4 years ago

3 0

Answer: Tan B = 0.2917 (16.26 degrees)

Sin B = 0.2800 (16.26 degrees)

Cos B = 0.9600 (16.26 degrees)

Step-by-step explanation: Please refer to the picture attached for details.

The right angled triangle LNB has been drawn with the sides labeled as 7, 24 and 25 as indicated. With angle B as the reference angle, we can now identify each side as follows;

Side 7 (opposite, facing the reference angle)

Side 24 (adjacent, between the reference angle and the right angle)

Side 25 (hypotenuse, facing the right angle).

Hence, using the trigonometric ratios,

Tan B = opposite/adjacent

Tan B = 7/24

Tan B = 0.2917 (16.26 degrees)

Sin B = opposite/hypotenuse

Sin B = 7/25

Sin B = 0.2800 (16.26 degrees)

Cos B = adjacent/hypotenuse

Cos B = 24/25

Cos B = 0.9600 (16.26 degrees)

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To determine a monthly budget for gasoline, Rachael determines that she can not spend more

IrinaK [193]

The solution of the given inequality is:

x ≤ 15.24

<h3>How to solve the inequality?</h3>

We know that the maximum that she can spend on gasoline is the 12% of $400.

That is:

(12%/100%)*$400 = 0.12*$400 = $48

Now, we know that each gallon of gas costs $3.15, then if x is the number of gallons of gas that she buys, we have the inequality:

x*$3.15 ≤ $48

To solve the inequality, we need to divide both sides by $3.15

x ≤ $48/$3.15

x ≤ 15.24

So the maximum number of gallons of gasoline that she can buy is 15 gallons (actually a little more).

If you want to learn more about inequalities:

brainly.com/question/18881247

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4 0

2 years ago

Please explain with working!!! Find the set of values of x that satisfy the inequality 9x^2-15x<6

Oksi-84 [34.3K]

Answer:

$-1/3$

Step-by-step explanation:

When solving a quadratic inequality, first solve it normally like you would for a normal quadratic equation. We have:

$9x^2-15x$

Ignore the less than sign and replace it with an equal sign and solve the quadratic for its zeros:

$9x^2-15x=6$

Subtract 6 from both sides:

$9x^2-15x-6=0$

Divide everything by 3:

$3x^2-5x-2=0$

Factor. Find two numbers that equal (3)(-2)=-6 that add up to -5.

-6 and 1 works. Thus:

$3x^2-6x+x-2=0\\3x(x-2)+1(x-2)=0\\(3x+1)(x-2)=0$

Find the x using the Zero Product Property:

$3x+1=0 \text{ or }x-2=0\\x=-1/3\text{ or }x=2$

Now, we need to replace the equal signs with symbols again. To do so, we need to test which symbol to place. Let's do the first zero first.

So, the first zero is:

$x=-1/3$

Assume that the correct symbol is >. Thus,

$x>-1/3$

Now, pick any number that is greater than -1/3. I'll pick 0 since it's the easiest. Now, plug 0 back into the very original inequality. If it works, then the sign is correct, if it doesn't, then simply use the opposite one. Therefore:

$9x^2-15x$