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Black_prince [1.1K]

3 years ago

10

What is the equation of the line, in general form, that passes through the point (-1, -1) and is parallel to the line whose equa

tion is x + y = 3? x - y + 2 = 0 x + y + 2 = 0 x + y - 2 = 0

1 answer:

Ksenya-84 [330]3 years ago

5 0

Answer:

Step-by-step explanation:

y = -x + 3

y + 1 = -(x + 1)

y + 1 = -x - 1

y = -x - 2

x + y + 2 = 0 is the solution

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Ax + By = C<br> Solve for y

Alenkinab [10]

<em>Greetings from Brasil....</em>

Let's isolate Y:

Ax + By = C

By = C - Ax

<h2>y = (C - Ax)/B</h2>

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Drupady [299]

The Multiplication Property of Zero.

It states "the product of any number and zero is zero". Even if there are more than one multiplier - it is still 0.

So 5 x 0 = 0

100 x 0 = 0

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etc.

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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20%7D%7Bxy%7D%20%20%5Ctimes%20%20%5Cfrac%7B%20%7B4xy%7D%5E%

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$\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
\cfrac{3x^2}{xy}\cdot \cfrac{4xy^2}{\frac{1}{y}}\implies \cfrac{3x^2}{xy}\cdot \cfrac{4xy^2}{y^{-1}}\implies \cfrac{3x^2x^1y^2}{xy^1y^{-1}}\implies \cfrac{3x^{2+1}y^2}{xy^{1-1}}
\\\\\\
\cfrac{3x^3y^2}{xy^0}\implies \cfrac{3x^3y^2}{x^1}\implies 3x^3y^2x^{-1}\implies 3x^{3-1}y^2\implies 3x^2y^2$

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3 years ago

What is a fraction has both a negative denominator and numerator?

liubo4ka [24]

Negative divided by negative makes a positive

6 0

3 years ago

Brainliest and 30 points please help

kolbaska11 [484]

Answer:

22. Perimeter = 52 units

Area = 160 Square Units

23. Notation form : $2 \times 10^{5}$

Standard Form : 200000

Step-by-step explanation:

22.

The formula for perimeter is

P = 2 (length + Width )

= 2 ( 2x+3x+1)

= 2(5x+1)

The Formula for Area of a rectangle is

A= length x width

A= $2x \times (3x+1)$

A= $6x^2+2x$

Now we have to find the Perimeter and Area for x = 5

P = 2(5 x 5 +1)

P= 2(26)

P=52 units

A= 6 x 5 x 5 + 2 x 5

A= 150 + 10

A= 160 square units

23.

A. By using rule of exponents , we can determine that both the results will be same.

B.

Miriam's calculation

$\frac{2.8 \times 10^{9}}{1.4 \times 10^{4}}$

$\frac{2.8}{1.4} \times 10^{9-4}$

$2 \times 10^5$

Priya's calculation

$\frac{2.8 \times 10^{2}}{1.4 \times 10^{-3}}$

$\frac{2.8}{1.4} \times 10^{2-(-3)}$

$2 \times 10^5$

Standard notation

$2 \times 10^5 = 200000$

4 0

3 years ago