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Lena [83]
3 years ago
8

What is the common difference in this sequence: 3, 11, 19, 27, 35?

Mathematics
1 answer:
bixtya [17]3 years ago
8 0
3, 11, 19, 27, 35.
The common difference;
11-3 or 19-11
=8
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At rehearsal for the school play, jack sings three times as many songs as Jennifer, and then dances to 5 more songs, just to sho
Brilliant_brown [7]

Step-by-step explanation:

3x+5=44

3x=44-5

3x=39

x=39÷3

x=13

6 0
2 years ago
Assume that​ women's heights are normally distributed with a mean given by mu equals 62.5 in​,and a standard deviation given by
Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with  

\mu = 62.5 in

\sigma = 2.2 in

the normal probability density function is given by  

f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}, then

(a) P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx = 0.5899

   (in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking P(\bar{X} < 63) where n = 37. \bar{X} is normally distributed with mean 62.5 in and standard deviation 2.2/\sqrt{37}. So, the probability density function is given by

g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}, and

P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0
3 years ago
Jack Purchased a new iPhone for $300. It is expected to lose 25% of its value each
asambeis [7]

Answer:

94.92

Step-by-step explanation:

300*(75/100)^4=94.92

8 0
3 years ago
What is the measure of angle A? A.118 B.120 C.130 D.720
stich3 [128]
The actual measure of angel A is actually 190
8 0
3 years ago
Read 2 more answers
I have 8 questions witch means 80 points answer correctly!
kolezko [41]
<h3>Answer : </h3>

\Large \pink{\tt \dfrac{35}{36}}

<h3>Solution :</h3>

\tt \dfrac{3}{4} + \dfrac{2}{9}

By taking LCM = 4 × 9 = 36

\tt = \dfrac{3 \times 9}{4 \times 9} + \dfrac{2 \times 4}{9 \times 4}

\tt = \dfrac{27}{36} + \dfrac{8}{36}

\tt = \dfrac{27 + 8}{36}

\tt = \dfrac{35}{36}

\pink{\tt \therefore \: Answer \: is \: \dfrac{35}{36}}

7 0
3 years ago
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