Answer:
graph 1 = greater than 1
graph 2 = 0
graph 3 = 0
graph 4 = less than 0
graph 5 - between 0 & 1
Sorry if anything is wrong!!
Answer:
18
Step-by-step explanation:
Answer:
53
Step-by-step explanation:
20-5y+2x
20-5(-3)+2(9)
20--15+18
cancel out the negative signs
20+15+18
=53
The solution to the problem is as follows:
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the genaral term is 5Cr(-1)^r 2^r x^(5-2r)
and so need 5-2r = -1 => r = 3
Coeff is then 5C3 (-1)^3 2^3 = -80
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