The quadratic formula gives which roots for the equation 2x^2+7x+-2
1 answer:
The quadratic expression is given 
where the constants are
Quadratic formula to find the roots is given as
x₁,₂ = [-b plus minus √(b)²-4ac)] ÷ 2a
Substitute a, b, and c from our expression we have
x₁,₂ = [-7 plus minus √(7)²-(4×2×-2)] ÷ 2(2)
x₁,₂ = [-7 plus minus√65] ÷ 4
from here we'll work out x₁ and x₂ separately
x₁ = (-7+√65) ÷ 4 = 0.266 (round to 3 dp)
x₂ = (-7-√65) ÷ 4 = -3.766 (round to 3 dp)
Quadratic formula to find the roots is given as
x₁,₂ = [-b plus minus √(b)²-4ac)] ÷ 2a
Substitute a, b, and c from our expression we have
x₁,₂ = [-7 plus minus √(7)²-(4×2×-2)] ÷ 2(2)
x₁,₂ = [-7 plus minus√65] ÷ 4
from here we'll work out x₁ and x₂ separately
x₁ = (-7+√65) ÷ 4 = 0.266 (round to 3 dp)
x₂ = (-7-√65) ÷ 4 = -3.766 (round to 3 dp)
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Answer:
This is possible.
Step-by-step explanation:
We can say that m<E=m<E, because of the Reflexive Property
Then, we have angles JKL and ELJ, which are equal through the peripheral angle theorem.
With these two angles, we can say that triangles ELK and EJL are similar, by the Angle-Angle Postulate (AA).
Then we can create this ratio through the Corresponding Parts of Similar Triangles Theorem, (CPST), .
With this ratio, we can cross multiply to get the desired result
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Hope this helps with your RSM problem
Yup, i caught ya.