Answer:
This is possible.
Step-by-step explanation:
We can say that m<E=m<E, because of the Reflexive Property
Then, we have angles JKL and ELJ, which are equal through the peripheral angle theorem.
With these two angles, we can say that triangles ELK and EJL are similar, by the Angle-Angle Postulate (AA).
Then we can create this ratio through the Corresponding Parts of Similar Triangles Theorem, (CPST), .
With this ratio, we can cross multiply to get the desired result
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Hope this helps with your RSM problem
Yup, i caught ya.
Answer:
Graphic is showed in the figure below
Step-by-step explanation:
To graph the equations given, let's do a table for positive values of x, and, by replacing it in the equation, let's calculate the value of y. Knowing the coordinate points (x,y) we can build the graphic.
<em>x y= x + 1/x² y = 1/x</em>
1 2 1
2 2.25 0.2
3 3.11 0.33
4 4.06 0.25
When x->0 both equations -> ∞, because lim(1/x) x->0 = ∞
The graphic is showed below. In red there is y = 1 + 1/x² and in blue y = 1/x
