(-x²-2x+6)+(-9x²-7x+6) = -x²-2x+6-9x²-7x+6 = -10x² - 9x + 12
Its the one at the very bottom. :)
Complex zeroes always occurs as conjugates.
For z = a + b i conjugate is: a - b i
Another zero is : 2 + 3 i.
Verification:
2 + 3 i + 3 - 3 i = - b/a
- b = 4, a = 1
( 2 + 3 i ) ( 2 - 3 i ) = c / a
4 - 9 i² = c / a
4 + 9 = c / a
c = 13
( x^4 - 4 x³ + 14 x² - 4 x + 13 ) : ( x² - 4 x + 13 ) = x² + 1
x² + 1 = 0
x² = -1, x = i, x = -i
The zeroes are: - i , i , 2 + 3 i, 2 - 3 i.
Answer:
One another zero of f ( x ) is 2 + 3 i.
Step-by-step explanation:STEP 1: Draw two straight, intersecting tangent lines onto the circle. The lines can be completely random. However, the process will be easier if you make them roughly square or rectangular.
STEP 2: Translate both of the lines to the other side of the circle. You will end up with four tangent lines forming a parallelogram or a rough rectangle.
STEP 3: Draw the diagonals of the parallelogram. The point where these diagonal lines intersect is the circle's center.
STEP 4: Check the accuracy of the center with a compass. The center should be on target as long as you didn't slip while translating the lines or when drawing the diagonals. Feel free to erase the parallelogram and diagonal lines.
Answer:
The explicit function is: 
And the number of lights after 33 weeks will be 252.
Step-by-step explanation:
Given that:
Total street lights = 153
Let x be the number of weeks
Then the number lights after x weeks will be 3x
This is a linear function where the y-intercept is 153 and slope is 3.
It can be written as: y = mx+b
The function is:
Putting the values for x will give us the number of total lights after that number of weeks.
To find, how many street lights were there at the end of 33rd week,
Putting x = 33
Hence.
The explicit function is:
And the number of lights after 33 weeks will be 252.
